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4 years ago

What is entropy and how is it related to string theory?

Physics

1 answer:

balu736 [363]4 years ago

5 0

Answer:

Explanation:

String theory proposes that the fundamental constituents of the universe are one-dimensional “strings” rather than point-like particles. String theory also requires six or seven extra dimensions of space, and it contains ways of relating large extra dimensions to small ones. In statistical mechanics, entropy is an extensive property of a thermodynamic system. It quantifies the number Ω of microscopic configurations that are consistent with the macroscopic quantities that characterize the system theyre related It later developed into superstring theory, which posits a connection called supersymmetry between bosons and the class of particles called fermions. Five consistent versions of superstring theory were developed before it was conjectured in the mid-1990s that they were all different limiting cases of a single theory in 11 dimensions known as M-theory. In late 1997, theorists discovered an important relationship called the AdS/CFT correspondence, which relates string theory to another type of physical theory called a quantum field theory.

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Robert is hosting a backyard barbecue. He uses a charcoal fire to grill the chicken. The chicken cooks, but it never touches the

dimaraw [331]

As the chicken cooks (and if it doesn't directly touch the fire), energy goes through the chemical, radiant, then thermal stages respectively.

The charcoal fire releases chemical energy. The heat of the fire is radiant, and the thermal (heat) of the fire cooks the chicken.

5 0

3 years ago

Read 2 more answers

Two circular loops carry identical currents, but the radius of one loop is twice that of the other.

Valentin [98]

The magnetic field at the center of the 2nd loop is half the magnetic field at the center of the 1st loop.

Explanation:

The magnetic field strength at the center of a current-carrying circular loop is

$B=\frac{\mu_0 I}{2R}$

where

$\mu_0$ is the vacuum permeability

I is the current

R is the radius of the loop

For the first circular loop, we have

$B_1 = \frac{\mu_0 I_1}{2R_1}$

The second loop has

$I_2 = I_1$ (same current)

$R_2 = 2R_1$ (twice the radius)

So, the magnetic field at the centre of the second loop is

$B_2 = \frac{\mu_0 I_2}{2R_2}=\frac{1}{2}(\frac{\mu_0 I_1}{2R_1})=\frac{B_1}{2}$

So, the magnetic field at the center of the 2nd loop is half the magnetic field at the center of the 1st loop.

Learn more about magnetic fields:

brainly.com/question/3874443

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#LearnwithBrainly

4 0

3 years ago

Una esfera de radio 0.4m tiene una masa de 300kg, se desea sumergir en agua para saber si flota o no. En este ejercicio use la d

iragen [17]

Answer:

La esfera no flotará pero se hundirá cuando se coloque en el agua porque su densidad es mayor que la del agua.

Explanation:

De la pregunta anterior, se obtuvieron los siguientes datos:

Radio (r) de la esfera = 0,4 m

Masa de esfera = 300 Kg

Densidad del agua = 1000 Kg / m³

A continuación, determinaremos el volumen de la esfera. Esto se puede obtener de la siguiente manera:

Radio (r) de la esfera = 0,4 m

Pi (π) = 3,14

Volumen (V) de la esfera =?

V = 4/3 πr³

V = 4/3 × 3,14 × 0,4³

V = 12,56 / 3 × 0,064

V = 0,27 m³

A continuación, determinaremos la densidad de la esfera. Esto se puede obtener como se ilustra a continuación:

Masa de esfera = 300 Kg

Volumen de esfera = 0,27 m³

Densidad de esfera =?

Densidad = masa / volumen

Densidad de la esfera = 300 / 0,27

Densidad de la esfera = 1111,11 Kg / m³

Comparando la densidad del agua y la de la esfera.

Sustancia >>>>>>> Densidad

Agua >>>>>>>>>>> 1000 Kg / m³

Esfera >>>>>>>>>> 1111,11 Kg / m³

De la ilustración anterior, podemos ver que la densidad de la esfera es mayor que la del agua.

Por lo tanto, la esfera no flotará sino que se hundirá cuando se coloque en el agua porque su densidad es mayor que la del agua.

4 0

3 years ago

Write the nuclear equation for the alpha decay of astatine-213.

Sonbull [250]

Answer:

hope this helpes!!

Explanation:

plz mark brainliest

7 0

3 years ago

In simple harmonic motion, the acceleration is proportional to In simple harmonic motion, the acceleration is proportional to:__

erik [133]

Answer:

e. all of the above

Explanation:

In simple harmonic motion, the acceleration is given as;

a = -ω²x = -(2πf)²x

$a_{max} = -\omega ^2A$

where;

ω is the angular velocity

f is the frequency

x is the displacement

A is the amplitude

Thus, In simple harmonic motion, the acceleration is proportional to the amplitude, velocity, frequency, and displacement.

The correct option is E.

"all of the above"

5 0

3 years ago