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lakkis [162]
3 years ago
6

PLEASE HELP ME! How do you think the swarms affect local populations of humans?

Physics
1 answer:
Volgvan3 years ago
5 0

Answer:

by temperature

Explanation:

cuz

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Help please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Tom [10]

A2 = 16 m^2

Explanation:

Application of Pascal's law:

F1/A1 = F2/A2

Given:

F1 = 50 N. A1 = 1 m^2

F2 = 800 N A2 = ?

A2 = (F2/F1)A1 = (800 N/50 N)(1 m^2)

= 16 m^2

5 0
3 years ago
Tasks
barxatty [35]

Answer:

NE DIYON INGILIZ MISIN SEN

7 0
2 years ago
Please help 40 points!!!!
Nutka1998 [239]

The answers to all the research related questions are written below.

<h3>What is atom?</h3>

Atom is the smallest unit of the element. Different elements have different size atoms and same element have same size atoms.

James Chadwick tracked down the neutron in 1932 and was conceded the Nobel Prize for science in 1935  held in a German prison camp for all of World War 1, he driven the British gathering inside the Manhattan Extend, in which the UK and Canada maintained the USA's World War 2 effort to build the world with nuclear bomb.

Chadwick and Rutherford were the first scientists who measured the nucleus radius using the alpha particles. He did Gold foil experiment to find the size of nucleus.

The contributions are present in the modern atomic model. They are: All matter consists of atoms. Atoms of the same element are the same in size and atoms of different elements are different. Atoms combine in whole-number ratios to form compounds.

Learn more about atoms.

brainly.com/question/1566330

#SPJ1

8 0
2 years ago
Which of the following is an example or an orginasm mantaining homeostasis
Kryger [21]

a cat grooming itself

8 0
3 years ago
The two speakers at S1 and S2 are adjusted so that the observer at O hears an intensity of 6 W/m² when either S1 or S2 is sounde
Zanzabum

Answer:

The minimum frequency is 702.22 Hz

Explanation:

The two speakers are adjusted as attached in the figure. From the given data we know that

S_1 S_2=3m

S_1 O=4m

By Pythagoras theorem

                                 S_2O=\sqrt{(S_1S_2)^2+(S_1O)^2}\\S_2O=\sqrt{(3)^2+(4)^2}\\S_2O=\sqrt{9+16}\\S_2O=\sqrt{25}\\S_2O=5m

Now

The intensity at O when both speakers are on is given by

I=4I_1 cos^2(\pi \frac{\delta}{\lambda})

Here

  • I is the intensity at O when both speakers are on which is given as 6 W/m^2
  • I1 is the intensity of one speaker on which is 6  W/m^2
  • δ is the Path difference which is given as

                                           \delta=S_2O-S_1O\\\delta=5-4\\\delta=1 m

  • λ is wavelength which is given as

                                             \lambda=\frac{v}{f}

      Here

              v is the speed of sound which is 320 m/s.

              f is the frequency of the sound which is to be calculated.

                                  16=4\times 6 \times cos^2(\pi \frac{1 \times f}{320})\\16/24= cos^2(\pi \frac{1f}{320})\\0.667= cos^2(\pi \frac{f}{320})\\cos(\pi \frac{f}{320})=\pm0.8165\\\pi \frac{f}{320}=\frac{7 \pi}{36}+2k\pi \\ \frac{f}{320}=\frac{7 }{36}+2k \\\\ {f}=320 \times (\frac{7 }{36}+2k )

where k=0,1,2

for minimum frequency f_1, k=1

                                  {f}=320 \times (\frac{7 }{36}+2 \times 1 )\\\\{f}=320 \times (\frac{79 }{36} )\\\\ f=702.22 Hz

So the minimum frequency is 702.22 Hz

5 0
3 years ago
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