Answer:
The metallic oxide is Li₂O
Explanation:
Let the metallic oxide be M₂O
Thus;
M₂O + H₂ = 2M + H₂O
Molar mass of M₂O = (2x + 16)
We assume Molar mass of M to be x.
We are told that 5.00 g of the metallic oxide produces 2.32 g of the metal.
By proportion, we can write the following;
5g of M₂O × (1 mole of M₂O/(2x + 16)) × (2 moles of M/1 mole of M₂O) = 2.32 g of M × 1 mole of M/x g of M
This cancels out to give us;
10/(2x + 16) = 2.32/x
Cross multiply to get;
10x = 2.32(2x + 16)
10x = 4.64x + 37.12
10x - 4.64x = 37.12
5.36x = 37.12
x = 37.12/5.36
x = 6.925 g/mol
The metal with a molar mass closest to this value of x is Lithium which has a molar mass of 6.94 g/mol
Thus the metal is Lithium and as such the metallic oxide is Li₂O
