We know that
A quadrilateral is inscribed in a circle if and only if the opposite angles are supplementary. ( Inscribed Quadrilateral Theorem)
so
m∠B+m∠D=180°
2x+(3x-5)=180
5x=180+5
5x=185
x=185/5
x=37°
m∠A=x+5-----> 37+5------> 42°
the answer is
m∠A is 42°
Let's call the stamps A, B, and C. They can each be used only once. I assume all 3 must be used in each possible arrangement.
There are two ways to solve this. We can list each possible arrangement of stamps, or we can plug in the numbers to a formula.
Let's find all possible arrangements first. We can easily start spouting out possible arrangements of the 3 stamps, but to make sure we find them all, let's go in alphabetical order. First, let's look at the arrangements that start with A:
ABC
ACB
There are no other ways to arrange 3 stamps with the first stamp being A. Let's look at the ways to arrange them starting with B:
BAC
BCA
Try finding the arrangements that start with C:
C_ _
C_ _
Or we can try a little formula; y×(y-1)×(y-2)×(y-3)...until the (y-x) = 1 where y=the number of items.
In this case there are 3 stamps, so y=3, and the formula looks like this: 3×(3-1)×(3-2).
Confused? Let me explain why it works.
There are 3 possibilities for the first stamp: A, B, or C.
There are 2 possibilities for the second space: The two stamps that are not in the first space.
There is 1 possibility for the third space: the stamp not used in the first or second space.
So the number of possibilities, in this case, is 3×2×1.
We can see that the number of ways that 3 stamps can be attached is the same regardless of method used.
Answer:
She worked 5 hours a day
Step-by-step explanation:
20 / 4 = 5
You got no graphs btw :/
But hope I help a lil bit :]
Answer:
y = 64
Step-by-step explanation:
Using the rule of logarithms
• 
x = n ⇔ x = 
Given
4 = 
, then
4 = 
Cube both sides
4³ = ()³, hence
y = 64
Answer:
The volume of shipping crate is 32 unit cubes.
Step-by-step explanation:
Given that:
Length of the crate = 4 units
Width of the crate = 2 units
Height of the crate = 4 units
Volume of shipping crate = Length * Width * Height
Volume of the crate = 4 * 2 * 4
Volume of crate = 32 unit cubes.
Hence,
The volume of shipping crate is 32 unit cubes.
