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3 years ago

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Maple syrup, which comes from the sap of maple trees, is a mixture of water and natural sugars. It's a clear, brown liquid. It's

homogeneous, and the sugars cannot be separated by filtration or centrifuge. What type of mixture is it? A. suspension, B. colloid, C. Solution.

1 answer:

ANTONII [103]3 years ago

3 0

C.) It's a Solution ..............

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Select the true statements about eicosanoids. a. Eicosanoids are broken down within seconds to inactive residues. b. Arachidonic

Evgen [1.6K]

Answer: the true statements about eicosanoids includes options A,B,D,E

Explanation:

EICOSANOIDS are mostly produced from the precursor arachidonic acid, a C20 polyunsaturated fatty acid. They are broken down within seconds to inactive residues after synthesis.High concentrations of eicosanoids are necessary for effective action.The three major types of eicosanoids includes:

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- leukotrienes.

Depending on the above types mentioned, they play a role in inflammation, pain, fever promotion, blood pressure regulation, and blood clotting. They also influence the immune response and certain respiratory and reproductive processes.

However, eicosanoids are NOT transported in the blood stream to their site of action RATHER they exert their effects on the tissue where they are synthesized.

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3 years ago

I spilled water on my computer and its dancing now

WARRIOR [948]

Amazing..............

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3 years ago

In one of his experiments, Lavoisier placed 10.0 grams of mercury (II) oxide into a sealed container and heated it. The mercury

inysia [295]

Oxygen gas produced : 0.7 g

<h3>Further explanation</h3>

Given

10.0 grams HgO

9.3 grams Hg

Required

Oxygen gas produced

Solution

Reaction⇒Decomposition

2HgO(s)⇒2Hg(l)+O₂(g)

Conservation of mass applies to a closed system, where the masses before and after the reaction are the same

mass of reactants = mass of products

mass HgO = mass Hg + mass O₂

10 g = 9.3 g + mass O₂

mass O₂ = 0.7 g

4 0

3 years ago

A chemist prepares a solution of aluminum sulfate Al2SO43 by weighing out 101.g of aluminum sulfate into a 200.mL volumetric fla

qaws [65]

Answer:

50.5 g/dL

Explanation:

From the question given above, the following data were obtained:

Mass of Al₂(SO₄)₃ = 101 g

Volume (V) = 200 mL

Concentration of solution (g/dL) =?

Next, we shall convert 200 mL to decilitre (dL).

This is illustrated below:

1 mL = 0.01 dL

Therefore,

200 mL = 200 mL / 1 mL × 0.01 dL

200 mL = 2 dL

Therefore, 200 mL is equivalent to 2 dL.

Finally, we shall determine the concentration of the solution in g/dL as follow:

Mass of Al₂(SO₄)₃ = 101 g

Volume (V) = 2 dL

Concentration of solution (g/dL) =?

Concentration of solution (g/dL) = mass /volume

Concentration of solution (g/dL) = 101/2

= 50.5 g/dL

Therefore, the concentration of the Al₂(SO₄)₃ solution is 50.5 g/dL

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4 years ago

A rigid tank is divided into two equal volumes. One side contains 2 kmol of nitrogen N2 at 500 kPa while the other side contains

k0ka [10]

Answer:

The partial pressure of the $CO_2$ in the final mixture is 200 kPa.

Explanation:

Pressure of nitrogen gas when the two tanks are disconnected = 500 kPa

Pressure of the carbon-dioxide gas when the two tanks are disconnected = 200 kPa

Moles of nitrogen gas = $n_1= 2 kmol$

Moles of carbon dioxide gas = $n_2=8 kmol$

After connecting both the tanks:

The total pressure of the both gasses in the tank = p = 250 kPa

According to Dalton' law of partial pressure:

Total pressure is equal to sum of partial pressures of all the gases

Partial pressure of nitrogen = $p_{N_2}^o$

Partial pressure of carbon dioxide= $p_{CO_2}^o$

$p_{N_2}^o=p\times \frac{n_1}{n_1+n_2}$

$p_{N_2}^o=250 kPa\times \frac{0.2}{0.2+0.8}=50 kPa$

$p_{CO_2}^o=p\times \frac{n_2}{n_1+n_2}$

$p_{CO_2}^o=250 kPa\times \frac{0.8}{0.2+0.8}=200 kPa$

The partial pressure of the $CO_2$ in the final mixture is 200 kPa.

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3 years ago