Answer:
321.6 g/Mol
Explanation:
mass of solvent in kilograms = 90g/1000 = 0.09 Kg
Given that;
ΔTf = Kf . m . i
Where;
Kf = freezing point constant = 4.25 °C/Kg mol
m = molality of the solution
i = Van't Hoff factor = 1 (since the substance is molecular)
ΔTf = freezing point of pure solvent - freezing point of solution
freezing point of pure solvent = 3 °C
ΔTf = 3 °C - 2.1 °C
ΔTf = 0.9 °C
0.9= 4.25 * 6.13/M/0.09 * 1
0.9= 26.0525/M * 1/0.09
0.9 = 26.0525/0.09 M
0.9 * 0.09M = 26.0525
M = 26.0525/0.9 * 0.09
M= 321.6 g/Mol
The balanced reaction is:
MnO2<span>(s) + 4HCl(aq) → Cl2(g) + MnCl2(aq) + 2H2O(l)
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We are given the amount of hydrochloric acid to be used for the reaction. This will be the starting point for the calculations.
1.82 mol HCl ( 1 mol Cl2 / 4 mol HCl) = 0.46 mol Cl2
Therefore, 0.46 mol of chlorine gas is produced for the reaction of hydrochloric acid and manganese oxide.
Answer: The last one
Explanation: because Im in the 8th grade and I did this in the 6th
GIVE BRAINLEIST LIKE U PROMISED
The reaction of acid, assuming HCl and calcium carbonate always produces a gas. The reaction is as follows:
2 HCl + CaCO3 --> CaCl2 + H2CO3
H2CO3, carbonic acid, is a weak acid that is unstable in water solutions at high concentrations. As such, it decomposes:
H2CO3 --> H2O + CO2
Then,
2 HCl + CaCO3 --> CaCl2 + H2O + CO2
The total ionic equation looks as follows:
2H+(aq) + 2 Cl-(aq) + CaCO3(s) --> Ca+2(aq) + 2 Cl-(aq) + H2O(l) + CO2(g)
Clearly, Cl- is a spectator ion as it is unchanged in the reaction. The net ionic reaction looks as follows:
2 H+(aq) + CaCO3(s) --> Ca+2(aq) + H2O(l) + CO2(g)
