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ki77a [65]
2 years ago
7

What feature of a chemical equation is used to balance the equation and make sure it obeys the law of conservation of mass?

Chemistry
2 answers:
gladu [14]2 years ago
6 0

Answer:

b.  Coefficient.

Explanation:

For example:

Zinc combines with oxygen to form zinc oxlde :

We have Zn and O2 forming ZnO:

2Zn + O2 = 2ZnO

The 2's before the Zn and ZnO balance the equation

taurus [48]2 years ago
5 0

Answer:

b) coefficient

Explanation:

Refer to this example:

CH4  +2  O2  →  CO2+  2  H2O

2 is used as a coefficient in this chemical equation.

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4 0
2 years ago
In the figure, which two lines appear to be parallel?
Ipatiy [6.2K]
I don’t understand. Is there a picture? Where are the options?
7 0
3 years ago
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If two atoms have a difference in electronegativity of 2.0, what type of tond do they have?
stellarik [79]

Answer:

Ionic

Explanation:

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3 0
3 years ago
Normally the capital ÎGo° for a reaction would be determined at standard temperature with each reactant at a concentration of 1
Arte-miy333 [17]

Answer:

d.-379 cal/mol

Explanation:

ΔG = ΔG⁰ + RT ln K

for equilibrium ΔG = 0

ΔG⁰ + RT ln K =0

ΔG⁰   =  -  RT ln K

PG ⇒ PEP

K = [ PEP ] / [ PG ]

= .68 / .32

= 2.125

ΔG⁰   =   - 1.987 x 273 x  ln 2.125

= - 409 Cal / mole

Option d is the nearest answer .

8 0
3 years ago
Traumatic acid contains 63.13% carbon, 8.830% hydrogen, and 28.03% oxygen. its molar mass is 228 g/mol. determine the empirical
Zina [86]
Q1)
firstly we need to determine the empirical formula of the compound. empirical formula is the simplest ratio of components in the compound.
percentages of the elements have been given, so lets assume we are calculating for a compound of 100g 
                                  C                               H                              O
mass                       63.13 g                    8.830 g                       28.03 g
molar mass             12 g/mol                   1 g/mol                      16 g/mol
number of moles     63.13/12                   8.830/1                      28.03/16
                                5.26                           8.830                           1.75
divide by the smallest number of moles 
                                5.26/1.75                   8.830/1.75                   1.75/1.75
                                = 3.01                        = 5.04                           =1
rounded off to the nearest whole numbers 
C - 3
H - 5
O - 1
therefore empirical formula = C₃H₅O

Q2)
we have to next determine the molecular formula of the compound 
molecular formula gives the actual composition of elements in the compound. 
since we know the empirical formula and molecular mass, we can find how many empirical units are in the molecular formula.
mass of empirical unit = Cx3 + Hx5 + Ox1
                                    = 12 g/mol x 3 + 1g/mol x 5 + 16 g/mol x 1
                                    = 36 + 5 + 16 = 57 g/mol
the molecular mass = 228 g/mol
then number of empirical units in the molecular formula = 228 / 57 = 4
therefore there are 4 empirical units 
then the molecular formula = 4 x empirical formula =4 (C₃H₅O)
molecular formula = C₁₂H₂₀O₄




3 0
3 years ago
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