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4vir4ik [10]
3 years ago
10

Round 4.051 to the nearest 100

Mathematics
2 answers:
Anit [1.1K]3 years ago
7 0

Answer:0 if its to the nearest one-hundred but 4.05 if its to the nearest one-hundredth

Step-by-step explanation:

Triss [41]3 years ago
3 0

Answer:

4.05

Step-by-step explanation:

the 0 is the the tenths place and the 5 is in the one hundredths place so when round you would round to 4.05

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3x−1−(x+3)=1 PLEASE HELP IDK HOW TO DO IT
torisob [31]

Answer:

x = 5/2

x = 2 1/2

x = 2.5

Step-by-step explanation:

3x - 1 - (x + 3) = 1

3x - 1 - x - 3 = 1

2x - 1 - 3 = 1

2x - 4 = 1

2x = 1 + 4

2x + 5

2x = 5

x = 5/2 → 2 1/2 → 2.5 ( can be written in any of these forms depending on what you need to do)

<em>Hope this helped! :)</em>

7 0
2 years ago
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Answer:

Rs.5500 is the correct answer .

4 0
2 years ago
Luca has 15
pav-90 [236]

Answer:10 question 1/2

Step-by-step explanation:

6 0
3 years ago
The bottom of Ignacio's desktop is 74.5cm from the floor. Ignacio's sits in his adjustable chair, and the tops of his legs are 4
dsp73

Answer:

Ignacio can make 5 clockwise rotations.

Step-by-step explanation:

Given that the Ignacio's legs are already at a height of 49.3cm and each rotation of the chair knob raises his legs another 4.8cm, we can set up an inequality to determine the number of rotations Ignacio could make without his legs touching the desk, which is at a height of 74.5cm:

4.8r + 49.3 < 74.5  where 'r' is equal to the number of rotations

The sum of the Ignacio's original leg height plus the amount of height increased from the rotations of the know must be less than 74.5 in order for his legs not to touch.  Now, solve for 'r':

Subtract 49.3 from both sides:  4.8r + 49.3 - 49.3 < 74.5 - 49.3 or 4.8r < 25.2

Divide 4.8 from both sides:  4.8r/4.8 < 25.2/4.8 or  r < 5.25

Since the number of rotations must be less than 5.25, he can make 5 complete rotations.  

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2 years ago
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Nimfa-mama [501]
It would be = because they shipped the same amount in each year
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3 years ago
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