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Ghella [55]
4 years ago
14

The fact that the sun rises and sets at different times during the day depending on the time of year is an example of a data tre

nd.
True or False
Physics
2 answers:
Arada [10]4 years ago
8 0

The actual answer was False, just took the test.

aliya0001 [1]4 years ago
4 0
The answer for this should be True.

may be wrong though!
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Is a football tackle an elastic or inelastic collision and why?
QveST [7]

If the kinetic energy of an object changes, then the collision is considered inelastic. This is regardless of whether the objects sticks together or not.

My best answer for this question would be D) inelastic, because kinetic energy is not conserved.

We can tell from the collision that it is not elastic.

Momentum is is conserved, it transfers to the other player.

Kinetic energy is not conserved, at it turns into internal friction.

I hope this helps! :)

3 0
3 years ago
Which waves have the highest frenquencies?
loris [4]
I believe the answer is B: UV
6 0
3 years ago
Read 2 more answers
Why is the pipe that carries the heated glycol from the box to the tank at an angle?​
Alik [6]

Answer:

Bok.............................

5 0
3 years ago
A wind blows at 100 km / h from the east. An aircraft points due north and sets off. In still air its speed is 150 km / h. What
goldenfox [79]

Answer:

180.28 km/h

Explanation:

Let north and south represent the positive and negative y axis and east and west represent the positive and negative x axis.

Given;

Velocity of wind vx= 100 km/s

Velocity of aircraft in still air vy = 150 km/s

The resultant velocity Vr is;

Vr = √(vx^2 + vy^2)

Vr = √(100^2 + 150^2)

Vr = 180.2775637731 km/h

Vr = 180.28 km/h

4 0
3 years ago
The normal force equals the magnitude of the gravitational force as a roller coaster car crosses the top of a 58-m-diameter loop
dedylja [7]

Answer:

16.87 m/s

Explanation:

To find the speed of the car at the top, when the normal force is equal the gravitational force, we just need to equate both forces:

N = P

m*a_c = mg

a_c is the centripetal acceleration in the loop:

a_c = v^2/r

So we have that:

mv^2/r = mg

v^2/r = g

v^2 = gr

v = \sqrt{gr}

So, using the gravity = 9.81 m/s^2 and the radius = 29 meters, we have:

v = \sqrt{9.81 * 29}

v = \sqrt{284.49} = 16.87\ m/s

The speed of the car is 16.87 m/s at the top.

5 0
3 years ago
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