Given that the rate of diffusion is 1 mm per 1 second. then the time it travels in 1 cm can be solve using the formula
t = d / r
where d is the distance
r is the rate
first, 1 cm is equal to 10 mm
t = 10 mm / ( 1 mm / s )
t = 10 s
Answer:
red supergiants is the answer
<h3>
Answer:</h3>
8.01 mol MgO
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
- Analyzing Reactions RxN
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Unbalanced] Mg + O₂ → MgO
[RxN - Balanced] 2Mg + O₂ → 2MgO
[Given] 8.01 moles Mg
[Solve] moles MgO
<u>Step 2: Identify Conversions</u>
[RxN] 2 mol Mg → 2 mol MgO
<u>Step 3: Stoich</u>
- [DA] Set up:

- [DA] Multiply/Divide [Cancel out units]:

Whenever electrons are shared or transferred between atoms there is a chemical reaction.
The electrons that are being transferred between atoms (two or more) create new bonds, which enable the production of a new substance. This process is then known as a chemical reaction.
Answer:
MM = 680g / mol
Explanation:
Hello! To calculate the molar mass of the compound (g / mol), I first have to calculate the molarity.
Molarity can be calculated from the osmotic pressure equation.
op = M * R * T
op = osmotic pressure = 28.1mmHg * (1 atm / 760mmHg) = 0.037atm
M = molarity
R = gas constant
T = temperature (K) = 20 ° C + 273.15 = 293.15K
M (mol / L) = op / R * T
M = 0.037atm / ((0.082 (atm * L) / (K * mol)) * 293.15K) = 0.0015mol / L
As I have the volume = 100ml * (1L / 1000ml) = 0.1L
I can calculate the amount of moles
n = M * V = 0.0015 * 0.1 = 0.00015mol
n = m / MM
m = mass
MM = molar mass
MM = m / n = 0.102g / 0.00015mol
MM = 680g / mol