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Andrews [41]
3 years ago
11

The equilibrium constant does not explicitly contain the concentration of the insoluble salt, whereas the expression for the sol

ubility-product constant has this concentration in the numerator.
Chemistry
1 answer:
Montano1993 [528]3 years ago
4 0

Explanation:

Ksp stands for equilibrium constant of the solubility product. The equilibrium constant for the dissolution of a sparingly soluble salt is the solubility product (Ksp) of the salt. Because the concentration of the salts which are pure solids is constant, it does not appear explicitly in the equilibrium constant expression.

The solubility product, Ksp expression for a salt is the product of the concentrations of the ions, with each concentration raised to a power equal to the coefficient of that ion in the balanced equation for the solubility equilibrium.

The solubility product constant (Ksp) describes the equilibrium between a solid and its constituent ions in a solution. The value of the constant identifies the degree to which the compound can dissociate in water. The higher the Ksp, the more soluble the compound is.

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Conversion factors are useful in solving problems in which a given measurement must be expressed in
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Conversion factors are useful in solving problems in which a given measurement must be expressed in some other units of measure.


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2 years ago
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8 0
3 years ago
If 2.00g of p-aminophenol ( 109.1 g/mol) reacts with 5.00 ml of acetic anhydride (102.1 g/mol and density = 1.08 g/ml), what mas
inna [77]
The complete reaction is as,

      4-Aminophenol + Acetic Anhydride → <span>Acetaminophen + Acetic Acid

First of all convert the ml of Acetic anhydrite to grams,
As,
                                Density  =  mass / volume
Solving for mass,
                                mass  =  Density </span>× Volume
<span>Putting values,
                                mass  =  1.08 g/ml </span>× 5ml
<span>
                                mass =  5.4 g of acetic anhydride

First Find amount of  acetic anhydride required to react completely with 2 g of p-Aminophenol,
As,
       109.1 g of p-aminophenol required  =  102.1 g of acetic anhydride
so,     2 g of p-aminophenol will require  =  X g of Acetic Anhydride

Solving for X,
                                X  =  (2 g </span>× 102.1 g) ÷ 109.1 g
 
                                X  =  1.87 g of acetic anhydride is required to be reacted.

But, we are provided with 5.4 g of Acetic Anhydride, means p-aminophenol is the limiting reactant and it controls the formation of product. Now Let's calculate for product,
As,
       109.1 g of p-aminophenol produced  =  180.2 g of <span>Acetaminophen
So    2.00 g of p-aminophenol will produce  =  X g of Acetaminophen

Solving for X,
                               X  =  (2.00 g </span>× 180.2 g) ÷ 109.1 g
 
                               X  =  3.30 g of Acetaminophen

Result:
          <span>If 2.00g of p-aminophenol reacts with 5.00 ml of acetic anhydride 3.30 g of acetaminophen is made.</span>
4 0
3 years ago
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