The sample has a new pressure of 274kPa. If at 105 kPa and 275K, a 220 mL sample of helium gas is contained in a cylinder with a moving piston. The sample is pushed till it has a 95.0 mL volume and 310K .
The macroscopic characteristics of ideal gases are related by the ideal gas law (PV = nRT). A gas is considered to be perfect if its particles (a) do not interact with one another and (b) occupy no space (have no volume). Where P= pressure V= volume and T = temperature.
From ideal gas equation
P₁V₁/T₁ =P₂V₂/T₂
105×220÷275 = P₂ ×95÷310
P₂= (105×220×310)÷(275×95)
P2= 7161000/26125
P2 = 274.105 kPa
Hence, the new pressure of helium gas is 274kPa
To know more about Ideas gas equation
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Answer: 1.99 mol h20
Explanation:
you have 36.030 g, trying to get it into mols
to get from g to mols, use the molar mass (periodic table)
36.030 g h20 (1 mol/18.02g) = 1.99 mol h20
Answer:
B
Explanation:
Boyle was known for rejecting Aristotle's theory basing it on the four elements (earth, air, fire, water).
The answer is c because thats the number when combined with a metal. +1 is when its combined with a nonmetal.
Answer:
4.858 g
Explanation:
Start with the formula
density = 
density = 1.98 g/mL
volume = 2.45 mL
mass = ??
rearrange the formula to solve for mass
(density) x (volume) = mass
Add in the substitutes and solve for mass
1.98 g/mL x 2.45 mL = 4.858 g
