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3 years ago

11

A calculus book weighing 20 N rests on the floor of a classroom. The reaction to the force of the floor on the book is a force o

f

1 answer:

umka21 [38]3 years ago

6 0

First off, Newtons dont measure weight, it measures force. Assuming thats a tyo, the answer is 20 N

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A ladybug falls into small hole. it takes 8.6s for the ladybug to hit the bottom. how deep is the hole? (take g=9.81 m/s²)

Jobisdone [24]

Answer:

Length of hole (s) = 362.77 m (Approx)

Explanation:

Given:

Time taken to hit the bottom (t) = 8.6 s

Acceleration due to gravity (g) = 9.81 m/s²

Find:

Length of hole (s) = ?

Computation:

Initial velocity (u) = 0 m/s

S = ut +1/2(gt²)

S = (0)(8.6) +1/2(9.81)(8.6)(8.6)

S = 1/2(9.81)(8.6)(8.6)

S = 1/2(9.81)(8.6)(8.6)

S = 362.7738

Length of hole (s) = 362.77 m (Approx)

4 0

3 years ago

The star Rho1 Cancri is 57 light-years from the earth and has a mass 0.85 times that of our sun. A planet has been detected in a

s344n2d4d5 [400]

Answer:

82780.42123 m/s

14.45 days

Explanation:

m = Mass of the planet

M = Mass of the star = $0.85\times 1.989\times 10^{30}\ kg=1.69065\times 10^{30}\ kg$

r = Radius of orbit of planet = $0.11\times 149.6\times 10^{9}\ m=16.456\times 10^{9}\ m$

v = Orbital speed

The kinetic and potential energy balance is given by

$\frac{GMm}{r^2}=\frac{mv^2}{r}\\\Rightarrow v=\sqrt{\dfrac{Gm}{r}}\\\Rightarrow v=\sqrt{\dfrac{6.67\times 10^{-11}\times 1.69065\times 10^{30}}{16.456\times 10^{9}}}\\\Rightarrow v=82780.42123\ m/s$

The orbital speed of the star is 82780.42123 m/s

The orbital period is given by

$t=\frac{2\pi r}{v}\\\Rightarrow t=\dfrac{2\pi \times 16.456\times 10^{9}}{82780.42123}\\\Rightarrow t=1249040.48419\ seconds=\dfrac{1249040.48419}{24\times 60\times 60}=14.45\ days$

The orbital period is 14.45 days

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3 years ago

Which form of Kepler’s third law can you use to relate the period T and radius r of a planet in our solar system as long as the

ser-zykov [4K]

T2=r In the form of Kepler's law that can use to relate the period T and radius of the planet in our solar systems

<u>Explanation:</u>

<u>Kepler's third law:</u>

Kepler's third law states that For all planets, the square of the orbital

period (T) of a planet is proportional to the cube of the average orbital radius (R).

In simple words T (square) is proportional to the R(cube) T²2 ∝1 R³3

T2 / R3 = constant = 4π ² /GM

where G = 6.67 x 10-11 N-m2 /kg2

M = mass of the foci body

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4 years ago

The main benefit you receive from using locomotor movements in a variety of activities is? Question 3 options:

Helga [31]

Answer:

run walk jump digk pwss botch

Explanation:

fudge

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3 years ago

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Pushing on the pump of a bottle of hand washing solution compresses a small spring which obeys Hooke's Law. If the potential ene

OLEGan [10]

U = 1/2 * k * x²

U = 0.003J
x = 0.0055m
k spring constant

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3 years ago