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masya89 [10]
3 years ago
11

A ladybug falls into small hole. it takes 8.6s for the ladybug to hit the bottom. how deep is the hole? (take g=9.81 m/s²)

Physics
1 answer:
Jobisdone [24]3 years ago
4 0

Answer:

Length of hole (s) = 362.77 m (Approx)

Explanation:

Given:

Time taken to hit the bottom (t) = 8.6 s

Acceleration due to gravity (g) = 9.81 m/s²

Find:

Length of hole (s) = ?

Computation:

Initial velocity (u) = 0 m/s

S = ut +1/2(gt²)

S = (0)(8.6) +1/2(9.81)(8.6)(8.6)

S = 1/2(9.81)(8.6)(8.6)

S = 1/2(9.81)(8.6)(8.6)

S = 362.7738

Length of hole (s) = 362.77 m (Approx)

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ACTIVITY BASED COSTING SYSTEMS

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A small, dense center that has a positive charge and is surrounded by moving electrons
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3 years ago
A horizontal circular platform rotates counterclockwise about its axis at the rate of 0.841 rad/s.0.841 rad/s. You, with a mass
kvv77 [185]

Answer:

The total angular momentum of the system is 217.46\ kg-m^2/s.

Explanation:

Given that,

Angular speed = 0.841 rad/s

Mass of platform = 72.1 kg

Speed = 1.17 m/s

Mass of poodle = 20.3 kg

Mass of mutt = 18.5 kg

Distance =3/4 of the platform's radius from the center

Mass of disk = 92.5 kg

radius = 1.87 m

Angular momentum is the product of moment of inertia and angular speed.

We need to calculate the angular momentum of person

L_{person} = I\omega

L_{person}=\dfrac{1}{2}mr^2\times\omega

L_{person}=\dfrac{1}{2}\times72.1\times(\dfrac{v}{\omega})^2\times\omega

L_{person}=\dfrac{1}{2}\times72.1\times(\dfrac{1.17}{0.841})^2\times0.841

L_{person}=58.679\ kg m^2/s

We need to calculate the angular momentum of platform

L_{platform}=\dfrac{1}{2}mr^2\times\omega

Put the value into the formula

L_{platform}=\dfrac{1}{2}\times92.5\times1.87^2\times0.841

L_{platform}=136.02\ kg m^2/s

We need to calculate the angular momentum of poodle

L_{poodle}=\dfrac{1}{2}mr^2\times\omega

Put the value into the formula

L_{poodle}=\dfrac{1}{2}\times20.3\times(\dfrac{1.87}{2})^2\times0.841

L_{poodle}=7.4625\ kg m^2/s

We need to calculate the angular momentum of mutt

L_{mutt}=\dfrac{1}{2}mr^2\times\omega

L_{mutt}=\dfrac{1}{2}\times18.5\times(\dfrac{3}{4}\times1.87)^2\times0.841

L_{mutt}=15.302\ kg m^2/s

We need to calculate the total angular momentum

L=L_{person}+L_{platform}+L_{poodle}+L_{mutt}

L=58.679+136.02+7.4625+15.302

L=217.46\ kg-m^2/s

Hence, The total angular momentum of the system is 217.46\ kg-m^2/s.

3 0
3 years ago
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