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sveta [45]
2 years ago
6

What is the interval for time

Physics
2 answers:
Varvara68 [4.7K]2 years ago
8 0
Amount of time between two given points in time
vladimir1956 [14]2 years ago
5 0
The amount of time between two given points in time; ex would be 3:00pm to 5:00pm is two hours
You might be interested in
Convert the normal temperature of human body from Celcius to Kelvin<br> and Fahrenheit scale.
Kay [80]

Answer:

the normal human body temperature in Celcius is 37°C, in Fahrenheit is 98.6°F, in Kelvin is 310°K

7 0
3 years ago
A satellite in earth orbit has a mass of 99 kg and is at an altitude of 2.02 106 m. (assume that u = 0 as r â â.) (a) what is th
Ierofanga [76]

(a)          What is the potential energy: PE = -G * M * m/r

 

Where: M is the mass of the earth which is 5.98 * 10^24 kg.

m is the mass of the satellite.

r is the space from the center of the earth to the satellite

 

To conclude this distance add the radius of the earth to the altitude. Radius of the earth is 6.38 * 10^6 meters.

 

 

r = 6.38 * 10^6 + 2.02 * 10^6 = 8.38 * 10^6

PE = 6.67 * 10^-11 * 5.98 * 10^24 * 99/8.38 * 10^6 = 4.71240095 * 10^9 J

 

 

(b) magnitude of the gravitational force exerted by the Earth

 

Fg = G * M * m/r^2

Fg = 6.67 * 10^-11 * 5.98 * 10^24 * 99/(8.38 * 10^6)^2 = 562.3078873 N

 

 

(c) There are no other forces that the satellite exert on the Earth. So therefore, it is 0.

8 0
3 years ago
A bullet is fired horizontally into an initially stationary block of wood suspended by a string and remains embedded in the bloc
UkoKoshka [18]

The ratio of the kinetic energy of the block/bullet system immediately after the collision to the initial kinetic energy of the bullet is 0.78 %.

<h3>Final velocity of the block/bullet system</h3>

Apply the principle of conservation of energy to determine the final velocity of the block/bullet system.

K.E = P.E

¹/₂mv² = mgh

¹/₂v² = gh

v² = 2gh

v = √2gh

where;

  • h is the maximum height reached by the system
  • v is the initial velocity of the system

v = √(2 x 9.8 x 1.1)

v = 4.64 m/s

<h3>Initial velocity of the bullet</h3>

Apply the principle of conservation of linear momentum.

m₁u₁ + m₂u₂ = v(m₁ + m₂)

where;

  • u₁ is the initial velocity of the bullet
  • u₂ is the initial velocity of the block
  • v is the final velocity after collision
  • m₁ is mass bullet
  • m₂ is mass of block

(0.0075)u₁ + (0.95)(0) = 4.64(0.0075 + 0.95)

0.0075u₁ = 4.4428

u₁ = 4.4428/0.0075

u₁ = 592.37 m/s

<h3>Initial kinetic energy of the bullet</h3>

K.Ei = ¹/₂m₁u₁²

K.Ei = ¹/₂(0.0075)(592.37)²

K.Ei = 1,315.88 J

<h3>Final kinetic energy of the block/bullet system</h3>

K.Ef = ¹/₂(m₁ + m₂)v²

K.Ef = ¹/₂(0.0075 + 0.95)(4.64)²

K.Ef = 10.31 J

<h3>Ratio of final kinetic energy to initial kinetic energy</h3>

= K.Ef/K.Ei x 100%

= (10.31 / 1,315.88) x 100%

= 0.78 %

Learn more about kinetic energy here: brainly.com/question/25959744

#SPJ1

4 0
2 years ago
QUESTION 45
Olin [163]
I do not know if it is correct but I think it is between B or C
3 0
3 years ago
Falling objects drop with an average acceleration of 9.8 m/sec/sec, or 9.8 m /s2. If an object falls from the top of a tall buil
Lena [83]

Use the velocity expression for uniform acceleration and solve for t: v = v0 + at. v0 is zero since the object is at rest. 49 m/s = a(t), and solve for t. t = 49 m/s / 9.8 = 5 seconds.

5 0
3 years ago
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