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lisov135 [29]
3 years ago
13

If two gases are present in a container, the total pressure in the container is equal to

Chemistry
1 answer:
dmitriy555 [2]3 years ago
8 0

Answer: the sum of the partial pressures of the individual gases.

Explanation:

According to Dalton's Law of partial pressure, the total pressure of a mixture of gases is equal to the sum of the partial pressures which each individual gas would exert if it were confined alone in the volume occupied by the mixture.

Hence, Ptotal = P1+ P2

where Ptotal is the total pressure

P1 and P2 are the partial pressures exerted seperately by the individual gases 1 and 2 that make up the mixture.

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Although I am solid, I am so light that I can float in any liquid listed on the chart. What am I?-----
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Answer:

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3 years ago
A chemical process dissolves 500 milligrams of iron oxide every 20 minutes. How long would it take this reaction to dissolve 2 l
stiv31 [10]

Answer:

36290 min = 604.8 hr.

Explanation:

  • Knowing that:

1 lbs = 453.59237 grams.

∴ 2 lbs = 907.18474 grams.

<em><u>Using cross multiplication:</u></em>

500 mg of iron oxide dissolved → 20 minutes.

907184.74 mg of iron oxide dissolved → ??? minutes.

<em>∴ The time needed to dissolve 2 lbs of iron oxide =</em> (907184.74 mg)(20 min)/(500 mg) = <em>36290 min = 604.8 hr.</em>

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2 years ago
How many grams are in 4 moles of aluminum phosphate
vladimir2022 [97]

Answer:

487.8116

Explanation:

4 0
3 years ago
Read 2 more answers
A scientist exam in two atoms. One has a nucleus with five protons in five neutron surrounded by five electrons. The other has a
grigory [225]

Answer:

C) They are not made of matter.

Explanation:

Case in which protons are inside of neutrons doesn't exist.

8 0
3 years ago
Using the Bohr model, determine the energy, in joules, necessary to ionize a ground-state hydrogen atom. Show your calculations.
lord [1]

Answer:

The energy required to ionize the ground-state hydrogen atom is 2.18 x 10^-18 J or 13.6 eV.

Explanation:

To find the energy required to ionize ground-state hydrogen atom first we calculate the wavelength of photon required for this operation.

It is given by Bohr's Theory as:

1/λ = Rh (1/n1² - 1/n2²)

where,

λ = wavelength of photon

n1 = initial state = 1 (ground-state of hydrogen)

n2 = final state = ∞ (since, electron goes far away from atom after ionization)

Rh = Rhydberg's Constant = 1.097 x 10^7 /m

Therefore,

1/λ = (1.097 x 10^7 /m)(1/1² - 1/∞²)

λ = 9.115 x 10^-8 m = 91.15 nm

Now, for energy (E) we know that:

E = hc/λ

where,

h = Plank's Constant = 6.625 x 10^-34 J.s

c = speed of light = 3 x 10^8 m/s

Therefore,

E = (6.625 x 10^-34 J.s)(3 x 10^8 m/s)/(9.115 x 10^-8 m)

<u>E = 2.18 x 10^-18 J</u>

E = (2.18 x 10^-18 J)(1 eV/1.6 x 10^-19 J)

<u>E = 13.6 eV</u>

5 0
3 years ago
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