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AveGali [126]
3 years ago
14

Why is graphite used as a lubricant

Chemistry
2 answers:
Korvikt [17]3 years ago
6 0

There are weaker covalent bonds between these layers, hence they can easily slide over each other. Due to this, it is a lubricant, since the layers slide over each other so easily. ... Graphite is a mineral made of loosely bonded sheets of carbon atoms, giving it a slippery texture that makes it a very effective lubricant.

tigry1 [53]3 years ago
6 0

Answer:

Carbon atoms form STRONG bonds within each graphite layer but weak bonds between layers.

Explanation:

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Marina CMI [18]

Answer:

B.90.5 g

Explanation:

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6 0
3 years ago
Which pair of elements has the most similar Lewis structures?
jonny [76]

Answer: C.)

Explanation:

8 0
2 years ago
The molecule CH20 contains two single bonds and one double bond.<br> True<br> False
dem82 [27]

Answer:

True

Explanation:

The molecule CH20 contains two single bonds and one double bond.

6 0
3 years ago
If a temperature increase from 21.0 ∘c to 35.0 ∘c triples the rate constant for a reaction, what is the value of the activation
Airida [17]

Answer:

59.077 kJ/mol.

Explanation:

  • From Arrhenius law: <em>K = Ae(-Ea/RT)</em>

where, K is the rate constant of the reaction.

A is the Arrhenius factor.

Ea is the activation energy.

R is the general gas constant.

T is the temperature.

  • At different temperatures:

<em>ln(k₂/k₁) = Ea/R [(T₂-T₁)/(T₁T₂)]</em>

k₂ = 3k₁ , Ea = ??? J/mol, R = 8.314 J/mol.K, T₁ = 294.0 K, T₂ = 308.0 K.

ln(3k₁/k₁) = (Ea / 8.314 J/mol.K) [(308.0 K - 294.0 K) / (294.0 K x 308.0 K)]

∴ ln(3) = 1.859 x 10⁻⁵ Ea

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4 0
3 years ago
How many moles of chloride ions are there in 2.5 L of 5 M magnesium chloride?
castortr0y [4]

Answer:

n_{Cl^-}=25molCl^-

Explanation:

Hello,

In this case, since the given 5-M concentration of magnesium chloride is expressed as:

5\frac{molMgCl_2}{L}

We can notice that one mole of salt contains two moles of chloride ions as the subscript of chlorine is two, in such a way, with the volume of solution we obtain the moles of chloride ions as shown below:

n_{Cl^-}=5\frac{molMgCl_2}{L}*\frac{2molCl^-}{1molMgCl_2} *2.5L\\\\n_{Cl^-}=25molCl^-

Best regards.

4 0
3 years ago
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