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AveGali [126]
3 years ago
14

Why is graphite used as a lubricant

Chemistry
2 answers:
Korvikt [17]3 years ago
6 0

There are weaker covalent bonds between these layers, hence they can easily slide over each other. Due to this, it is a lubricant, since the layers slide over each other so easily. ... Graphite is a mineral made of loosely bonded sheets of carbon atoms, giving it a slippery texture that makes it a very effective lubricant.

tigry1 [53]3 years ago
6 0

Answer:

Carbon atoms form STRONG bonds within each graphite layer but weak bonds between layers.

Explanation:

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If a sample of air in a school container was heated, would the percentage of oxygen in the air increase, decrease, or remain unc
Viktor [21]

Answer:

increase

Explanation:

Let's suppose we have a sample of air in a closed container. We heat the container and we want to predict what would happen to the pressure.

According to Gay-Lussac's law, the pressure of a gas is directly proportional to its absolute temperature.

Thus, if we increased the temperature of the air by heating it, its pressure would increase.

If a sample of air in a closed container was heated, the total pressure of the air would increase.

5 0
3 years ago
A 2.1−mL volume of seawater contains about 4.0 × 10−10 g of gold. The total volume of ocean water is about 1.5 × 1021 L. Calcula
Fiesta28 [93]

Answer:

Total worth of gold in the ocean = $5,840,000,000,000,000

Explanation:

As stated in the question above, 4.0 x 10^-10 g of gold was present in 2.1mL of ocean water.

Therefore, In 1 L of ocean water there will be,

(4.0 x 10^-10)/0.0021

= 1.9045 x 10^-7 g of gold per Liter of ocean water.

So in 1.5 x 10^-21 L of ocean water, there will be

(1.9045 x 10^-7) * (1.5 x 10^-21)

= 2.857 x 10^14 g of gold in the ocean.

1 gram of gold costs $20.44, that is 20.44 dollars/gram. The total cost of the gold present in the ocean is

20.44 * (2.857 x 10^14)

= $5,840,000,000,000,000

8 0
3 years ago
I am in desperate need of help will give 40 points to whoever helps me!!!!! I have a quiz tomorrow but I have no idea how to do
serious [3.7K]
All of the questions here are pertaining to the colligative properties of a solution and the preparation of solutions. Maybe, it would be best if you understand the equations to be used in order to answer these questions.<span>
Freezing point depression or Boiling point elevation:

</span><span>ΔT = -K (m) (i)

</span>ΔT is the change in the freezing point or the boiling point not the freezing point/boiling point. Therefore, it should be added to the original value of the property of the solvent. 
<span>
K is a constant called the molal freezing point depression constant and for the boiling point is the boiling point elevation constant. It is a property of the solvent. 
</span><span>
m is the concentration of the solute in the solvent in terms of molality or kg solute/kg solvent. 
</span><span>
i is the vant hoff factor which will represent the number of ions which the solute dissociates when in solution.</span>
5 0
3 years ago
8. Which gas contributes the largest part of air? *
timurjin [86]

Answer:

Nitrogen

Explanation:

Nitrogen present 78% in the earth's atmosphere

5 0
3 years ago
Using the following thermochemical data, what is the change in enthalpy for the following reaction?
slavikrds [6]

Answer:

D. -120.9 kJ

Explanation:

According to Hess's law ,the total enthalpy change for a reaction is the sum of all changes regardless of the stages or the steps of the reaction.

CaO + 2HCl \rightarrow CaCl_{2} + H_{2}O\ (\Delta H = -186\ kJ)....(1)

CaO + H_{2}O\rightarrow Ca(OH)_{2}\ (\Delta H = - 65 \ kJ)

(this reaction should be reversed in order to reach the required reaction )

On reversing the reaction the sign of \Delta H get reversed.

(In this case change sign from '-' to'+'. Hence  \Delta H = + 65 kJ)

CaO + 2HCl \rightarrow  CaCl_{2} + H_{2}O\ (\Delta H = - 186\ kJ)....(1)

Ca(OH)_{2}   \rightarrow  CaO + H_{2}O\ (\Delta H = + 65 kJ )......(2)

Adding equation (1) and (2)

Ca(OH)_{2} + 2HCl \rightarrow CaCl_{2} + 2H_{2}O[tex][tex]Delta H = - 186 + 65 = - 121\kJ

Delta H = - 121\kJ (It is nearly equal to -120.9 kJ)

7 0
3 years ago
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