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Anastaziya [24]

4 years ago

6

Problem page write a balanced half-reaction for the reduction of solid manganese dioxide mno2 to manganese ion mn 2 in acidic aq

ueous solution. be sure to add physical state symbols where appropriate.

1 answer:

ale4655 [162]4 years ago

6 0

In a reduction reaction, some electrons are gained by the substance being reduced. The balanced half-reaction to this would be:

<span>MnO2(s) + 4 H+ (aq) + 2e ---> Mn^2+ (aq) + 2 H2O (aq)</span>

<span>It is called balanced reaction since the number of each element in the left side is equal to the number of each element on the right side.</span>

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IgorLugansk [536]

Explanation:

The given data is as follows.

Air is at $75^{o}F$ and 14.6 psia.

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(a) Formula to calculate hydraulic radius $(r_{H})$ is as follows.

$r_{H} = \frac{\text{free flow area}}{\text{wet perimeter}}$

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= $\frac{1}{3}$ ft

Formula for equivalent diameter is as follows.

$D_{eq} = 4 \times r_{H}$

= $4 \times \frac{1}{3} ft$

= $\frac{4}{3}$ ft

(b) Formula for velocity floe is as follows.

Q = VA

V = $\frac{Q}{A}$

= $\frac{48000}{2 \times 1}$ ft/min

= 24000 ft/min

(c) Formula to calculate Reynold's number is as follows.

$R_{e}$ = $\frac{D \times V \times \rho}{\mu}$

= $\frac{\frac{4}{3} \times 24000 \times 0.0744}{0.0443}$ (as $\rho = 0.0744 lb/ft^{3}$ and $\mu$ = 0.0443 lb/ft. hr)

= 53742.66 hr/min

As 1 hr = 10 min. So, $53742.66 hr/min \times \frac{60 min}{1 hr}$

= 3224559.6

(d) Formula to calculate pressure drop $(\Delta P)$ is as follows.

$\frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}$

Putting the given values into the above formula as follows.

$\frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}$

= $\frac{4 \times 0.00015 \times 100 \times 0.0744 \times (24000)^{2}}{2 \times \frac{4}{3} \times {4}{3}}$

= 6.238 $lb/ft^{2}$

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3 years ago

PLEASE HELP SOMEONE PLEASEEEE

crimeas [40]

Answer:

the answer is b

hope this helps you!!

Have a lovely day!

-millie :D

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