Answer:
d= 50.23 g/cm³
Explanation:
Given data:
radius = 137.9 pm
mass is = 5.5 × 10−22 g
density = ?
Solution:
volume of sphere= 4/3π r³
First of all we calculate the volume:
v= 4/3π r3
v= 1.33× 3.14× (137.9)³
v= 1.33 × 3.14 × 2622362.939 pm³
v= 1.095 × 10∧7 pm³
v= 1.095 × 10∧-23 cm³
Formula:
Density:
d=m/v
d= 5.5 × 10−22 g/ 1.095 × 10∧-23 cm³
d= 5.023 × 10∧+1 g/cm³
d= 50.23 g/cm³
274 amu
Explanation:
Atomic weight of Na = 23
Atomic weight of Sio3 = 76
then,
molecular weight of Na2Sio3 = add 23*2 and 76*3
= 46 and 228
= 274 amu
C. It is a relationship that is supported by experiments
Juan measured the temperature of salt water. He then added 273 to the measured value. The conversion is Juan most likely doing would be from Celsius to Kelvin. <span>Zero on the </span>Celsius<span> scale (0 °</span>C<span>) is now defined as the equivalent to 273.15 </span>K<span>, with a temperature difference of 1 deg </span>C<span> equivalent to a difference of 1 </span><span>K.</span>