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3 years ago

Examples of Cardiovascular Endurance ( check all that apply)

Physics

1 answer:

sveta [45]3 years ago

7 0

Answer:

Cardiorespiratory endurance is the level at which your heart, lungs, and muscles work together when you're exercising for an extended period of time.

...

Other activities
running or jogging.
swimming.
cycling.
dancing.
boxing.
aerobics or similar activities.
any active sport.

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A system for specifying the precise of objects in space and time

german

The answer is frame of reference ( system ).
Frame of reference <span>is a physical concept related to state of motion.

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4 years ago

What is the main energy source that causes changes in the atmosphere of Earth?

Wittaler [7]

Answer:

C is the correct answer.

6 0

3 years ago

Read 2 more answers

State the kinematic quantity that is equivalent to the slope of a position-time graph

Anni [7]

The figure shows the arrangement of given data.

The displacement is considered along X direction and time along Y direction.

The slope of the graph is given by tan θ

So tan θ = Δx/Δt = Velocity between those two points considered for finding slope of graph.

So slope of position time is graph is equivalent to kinematic quantity Velocity.

6 0

3 years ago

A device that transforms electrical energy to mechanical energy is a

yarga [219]

Answer:

Electric Motor

Explanation:

There are mainly two types of machines for inter-conversion between mechanical energy and electrical energy as under:

Motor
Generator

Motor is a device which converts electrical energy into a mechanical whereas generator does the exact opposite of motor.

There are 2 types of motors:

AC Motor - Converts alternating current into mechanical energy

DC Motor - Converts direct current into mechanical energy

4 0

4 years ago

A +15 nC point charge is placed on the x axis at x = 1.5 m, and a -20 nC charge is placed on the y axis at y = -2.0m. What is th

IceJOKER [234]

Answer: $E=75\ N/m$

Explanation:

Given

First charge of $q_1=15\ nC$ is placed at $x=1.5\ m$

Second charge $q_2=-20\ nC$ is placed at $y=-2\ m$

Electric field is given by

$E=\frac{kq}{r^2}$

Electric field due to $q_1$ is away from it

$E_1=\frac{9\times 10^9\times 15\times 10^{-9}}{(1.5)^2}$

$E_1=60\ N/m$

Electric field due to $q_2$

$E_2=\frac{9\times 10^9\times 20\times 10^{-9}}{2^2}$

$E_2=45\ N/m$

Net electric field will be vector addition of two

$\vec{E_{net}}=\vec{E_1}+\vec{E_2}$

$\vec{E_{net}}=-60\hat{i}-45\hat{j}$

Magnitude of Electric field is

$E=\sqrt{60^2+45^2}$

$E=75\ N/m$

8 0

3 years ago