Answer:
D) both groups are equatorial.
Explanation:
To solve this question we can start by drawing the molecule in using the <u>structure of the hexagon</u>. In this structure, we have the methyl group on carbon 1 and the terbutyl group on carbon 3, additionally, if we have a cis structure both groups must have the same type of bond (in this case the wedge bond). (See figure 1)
When we write the <u>chair structure</u>, we must keep the same structure. That is, methyl must be on carbon 1 and terbutyl on carbon 3. Also, the cis configuration must be maintained. With this in mind, we can choose the <u>equatorial configuration</u> for methyl on carbon 1 (since the position equatorial is the one that has <u>less steric impediment and more stability</u>). If this is true for carbon 1, we must place the terbutyl group on carbon 3 in the same configuration (i.e. cis). Therefore, on carbon 3 we must place the tert-butyl down on carbon 3, that is, in the <u>equatorial position</u>. (See figure 1).
Therefore, in the chair-like structure, both groups must be in an equatorial position.
I hope it helps!
According to the ideal gas law, partial pressure is inversely proportional to volume. It is also directly proportional to moles and temperature. At equilibrium in the following reaction at room temperature, the partial pressures of the gases are found to be PN2 = 0.094 atm, PH2 = 0.039 atm, and PNH3 = 0.003 atm.
<h3>Equilibrium partial pressures</h3>
The initial partial pressures of CO and water are 4.0 bar and 4.0 bar respectively.
The equilibrium partial pressures (in the bar) of CO, H2O, CO2, and H2 are 4−p,4−p, and respectively.
Let p bar be the equilibrium partial pressure of hydrogen.
The expression for the equilibrium constant is
Kp=PCOPH2OPCO2PH2=(4−p)(4−p)p×p=0.1
p=1.264−0.316p
p=0.96 bar.
To learn more about equilibrium constant visit the link
brainly.com/question/10038290
#SPJ4
Answer:
Explanation:
We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 16.04 32.00 44.01 18.02
CH₄ + 2O₂ → CO₂ + 2H₂O
m/g: 10.0 40.0
1. Moles of CH₄
2. Mass of CO₂
(i) Calculate the moles of CO₂
The molar ratio is (1 mol CO₂ /1 mol CH₄)
(ii) Calculate the mass of CO₂
3. Mass of H₂O
(i) Calculate the moles of H₂O
The molar ratio is (2 mol H₂O /1 mol CH₄)
(ii) Calculate the mass of H₂O
HClO4 +NaOH -----> NaClO4 + H2O
moles of NaOH = (0.0832 x 50 ) /1000= 4.16 x10^-3 moles
since the mole ratio of HClO4 to NaOH is 1:1 the moles of HClO4 is also 4.16 x 10^-3 moles
volume of HClO4 is therefore = moles/ molarity
that is 4.16 x 10^-3mol/ 0.167 mol/L= 0.0249L
multiply by 1000 to convert to ml
0.0249 x 1000= 24.9 ml