Answer:
only ten meters north from starting point
Explanation:
We know from the question that the Mass of the elastic object m = 0.00040 kg
Its Spring Constant is given as k = 40.0 N/m
Velocity required when the object is launched V = 16.0 m/s
Distance the elastic object has to be stretched from the equilibrium x = ?
We can use Conservation of Energy in this case, which tells us that
Elastic Potential Energy stored in the elastic object = Kinetic energy gained by it when released
We see that the 1/2 cancels from both sides and we are left with
Making x the subject of the formula, we have
Plugging in the numbers and solving for x, we get
Therefore, x = 0.05 m
The object has to be stretched by 0.05 m from its equilibrium position.
Answer:
Explanation:
Given that,
The radius o Earth, R = 6,357,000 m
Mass of the Earth, M = 5.972 × 10²⁴ kg
The mass of an elephant, m = 6000 kg
We need to find the force of gravity on the elephant. The force acting between two objects is given by :
So, the required force of gravity on the elephant is .
Answer:
hange in value is because the observer and the source has a relatively high speed
Explanation:
The emission of a molecular with is always the same, the reason why they change in value is because the observer and the source has a relatively high speed.
As the energy of the beam varies inversely with the wavelength, this shift is due to the fact that the earth and the cloud are moving away from each other.
If we want to find the velocity eta value we must use the relativistic Doppler effect
f ’= fs √ [(1- v / c) / (1 + v / c)]
According to Einstein's Theory of Relativity, an object at rest experiences the time differently from an object moving: a moving clock would be slower than a resting clock.
Two objects experiencing the same acceleration, do experience the same time dilation, therefore a person on Earth's surface experiencing a gravitational acceleration of 9.8m/s² will feel the same effects of a person on a spaceship accelerating at 9.8m/s².
Hence, the correct answer is: <span>D) Acceleration in space and gravity on Earth have the same effects on objects.
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