Answer:
v= 0.0316 m/s
Explanation:
We need to use the Doppler Effect defined as the change in frequency of a wave in relation to an observer who is moving relative to the wave source.
Notation
Let v= magnitude of the heart wall speed
V= speed of sound
fh= the frequency the heart receives (and reflects)
fi= original frequency
ff= reflected frequency
fb= frequency for the beats
Apply the Doppler Effect formula
Since the heart is moving observer then the device is a stationary source, and we have this formula
fh = [(V+ v)/(v)] fi (1)
We can consider the heart as moving source and the device as a stationary observer, and we have this formula
ff = [(V)/(V-v)] fh (2)
The frequency for the beats would be the difference from the original and the reflected frequency
fb = ff -fi (3)
Replacing equations (1) and (2) into equation (3) we have:


fb = fi(V+v -V+v)/(V-v)

Solving for v we have:


Answer: B.
but the resistance is lower in the parallel circuit.
Explanation:
A circuit with parallel connections has a lower total resistance than the resistors connected in series. This is consistent with conservation of charge. The power dissipated by each resistor is considerably higher in parallel than when connected in series to the same voltage source.
Due to the difference ofwavelength, blue has short wavelenght compared with red(red has long wavelength)
Answer: True
Explanation: A knowledge engineer is a professional who works to improve and builds with the aid of science and also implements advanced logic and AI( artificial intelligence) in computer systems in order to investigate particular issues.
A knowledge engineer also helps tries to emulate the judgements of man.
Since you are part of the team involved in discovering errors in the electronic spread sheet you are a knowledge engineer.
m₁ = 2.3 kg <span>
θ₁ = 70° </span><span>
θ₂ = 17° </span><span>
g = 9.8 m/s²
->The component of the gravitational force on m₁ that is parallel down the incline is: </span><span>
F₁ = m₁ × g × sin(θ₁) </span><span>
F₁ = (2.3
kg) × (9.8 m/s²) × sin(70°) = 21.18 N </span><span>
->The component of the gravitational force on m₂ that is parallel down the incline is: </span><span>
F₂ = m₂ × g × sin(θ₂) </span><span>
F₂ = m₂ × (9.8 m/s²) × sin(70°) = m₂ × (2.86 m/s²) </span><span>
Then the total mass of the system is:
m = m₁ + m₂ </span><span>
m = (2.3 kg) + m₂ </span><span>
If it is given that m₂ slides down the incline, then F₂ must be bigger than F₁, </span><span>
and so the net force on the system must be:
F = m₂×(2.86
m/s²) - (21.18 N) </span><span>
Using Newton's second law, we know that
F = m × a
So if we want the acceleration to be 0.64 m/s², then
m₂×(2.86
m/s²) - (21.18 N) = [(2.3 kg) + m₂] ×
(0.64 m/s²) </span><span>
m₂×(2.86
m/s²) - (21.18 N) = (1.47 N) + m₂×(0.64
m/s²) </span><span>
m₂×(2.22
m/s²) = (22.65 N) </span><span>
m₂<span> = 10.2
kg</span></span>