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Fiesta28 [93]
3 years ago
5

I need help asap. #3, 12points

Physics
1 answer:
WINSTONCH [101]3 years ago
7 0

Answer:

-10C= Solid

10C= Liquid

50C= Liquid

90C= Liquid

110C= Gas

120C= Gas

Explanation:

Below 0 degree C (Celsius), water is frozen means it is in the form of ice. After 0 degree, once we keep it in room temperature, the ice starts becoming liquid (water), and once we heat water, after 100 degree C (Celsius) water starts boiling and thus starts entering gaseous state.

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What mass of water must evaporate from the skin of a 70.0 kg man to cool his body 1.00 ∘C? The heat of vaporization of water at
romanna [79]

Answer:

100 cc

Explanation:

Heat released in cooling human body by t degree

= mass of the body x specific heat of the body x t

Substituting the data given

Heat released by the body

= 70 x 3480 x 1

= 243600 J

Mass of water to be evaporated

= 243600 / latent heat of vaporization of water

= 243600 / 2420000

= .1 kg

= 100 g

volume of water

= mass / density

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100 cc

1 / 10 litres.

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3 years ago
Choose the correct words from the box to complete the definition of resistance.
zzz [600]

Answer:

Opposition of passing a electric circuit

6 0
2 years ago
Constant Acceleration Kinematics: Car A is traveling at 22.0 m/s and car B at 29.0 m/s. Car A is 300 m behind car B when the dri
Ainat [17]

Answer:

The taken is  t_A  = 19.0 \ s

Explanation:

Frm the question we are told that

  The speed of car A is  v_A  =  22 \ m/s

   The speed of car B is  v_B  = 29.0 \ m/s

     The distance of car B  from A is  d = 300 \ m

     The acceleration of car A is  a_A  = 2.40 \ m/s^2

For A to overtake B

    The distance traveled by car B  =  The distance traveled by car A - 300m

Now the this distance traveled by car B before it is overtaken by A is  

          d = v_B * t_A

Where t_B is the time taken by car B

Now this can also be represented as using equation of motion as

      d = v_A t_A  + \frac{1}{2}a_A t_A^2 - 300

Now substituting values

       d = 22t_A  + \frac{1}{2} (2.40)^2 t_A^2 - 300

Equating the both d

       v_B * t_A = 22t_A  + \frac{1}{2} (2.40)^2 t_A^2 - 300

substituting values

   29 * t_A = 22t_A  + \frac{1}{2} (2.40)^2 t_A^2 - 300

   7 t_A = \frac{1}{2} (2.40)^2 t_A^2 - 300

  7 t_A =1.2 t_A^2 - 300

   1.2 t_A^2 - 7 t_A - 300  = 0

Solving this using quadratic formula we have that

     t_A  = 19.0 \ s

7 0
3 years ago
You are working in the finance department of Innotech Ltd (INT). The Company has spent $5 million
lozanna [386]

Answer: The Company has spent $5 million in research and development over the past 12 months developing cutting-edge battery technology which will be incorporated ...

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5 0
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Gravitational force is affected by: a. mass c. distance b. weight d. both a and c
NikAS [45]
<span>Gravitational force is affected by: a. mass c. distance b. weight d. both a and c

Mass.

</span>When an object is above the Earth's surface it hasgravitational potential<span> energy (GPE). The amount of GPE an object has depends on its mass and its height above the Earth's surface</span><span>


</span>
6 0
3 years ago
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