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Studentka2010 [4]
4 years ago
10

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!

Physics
1 answer:
Arada [10]4 years ago
5 0

Answer:D

Explanation: both variables change in the same direction. An increase in one variable leads to an increase in the other, a decrease in one lead to a decrease the another

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A heat pump used to heat a house runs about one-third of the time. The house is losing heat at an average rate of 22,000 kJ/h. I
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The power that heat pump draws when running will be 6.55 kj/kg

A heat pump is a device that uses the refrigeration cycle to transfer thermal energy from the outside to heat a building (or a portion of a structure).

Given a heat pump used to heat a house runs about one-third of the time. The house is losing heat at an average rate of 22,000 kJ/h and if the COP of the heat pump is 2.8

We have to determine the power the heat pump draws when running.

To solve this question we have to assume that the heat pump is at steady state

Let,

Q₁ = 22000 kj/kg

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So,

Q₁ = 3(22000) = 66000 kj/kg

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COP = Q₁/ω

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ω = 66000 / 2.8

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Hence the power that heat pump draws when running will be 6.55 kj/kg

Learn more about heat pump here :

brainly.com/question/1042914

#SPJ4

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