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Cerrena [4.2K]
3 years ago
12

Could someone please help me with this problem? I’m thinking that they both will have the same force because they have the same

Fgrav and equal masses. Thanks in advance!

Physics
1 answer:
Simora [160]3 years ago
7 0
You would be correct
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A charged particle is moving perpendicular to a magnetic field in a circle with a radius r. An identical charge particle enters
emmasim [6.3K]

Answer:

<em>The second particle will move through the field with a radius greater that the radius of the first particle</em>

Explanation:

For a charged particle, the force on the particle is given as

F = \frac{mv^{2} }{r}

also recall that work is force times the distance traveled

work = F x d

so, the work on the particle = F x d,

where the distance traveled by the particle in one revolution = 2\pi r

Work on a particle = 2πrF = 2\pi mv^{2}

This work is proportional to the energy of the particle.

And the work is also proportional to the radius of travel of the particles.

Since the second particle has a bigger speed v, when compared to the speed of the first particle, then, the the second particle has more energy, and thus will move through the field with a radius greater that the radius of the first particle.

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Answer:

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Explanation

Check the attachment

4 0
3 years ago
If a car is moving to the left with constantvelocity, one can conclude thatthere mustbe no forces applied to the car.the netforc
Allisa [31]

Answer:

the net force applied to the car is zero.

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