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3 years ago

15

On a cold winters day if you left a cup of water sitting outside it could freeze heat is transferred out of the water describe t

he behavior of the water molecules and how temperature is affected enter your answer in the space provided

1 answer:

valkas [14]3 years ago

4 0

The water molecules would slow down, and as they slow down, the heat created from their movement would cease.

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A 1460-kg submarine rises straight up towards the surface. Seawater exerts both an upward buoyant force of 16670 N on the submar

Amiraneli [1.4K]

Answer:

a = 0.63 m/s²

Explanation:

given,

mass of submarine = 1460-kg

upward buoyant force = 16670 N

downward resistive force = 1150 N

submarine acceleration = ?

assuming g = 10 m/s²

now,

B - (R + mg) = ma

16670 - 1150 - 1460 × 10 = 1460 × a

1460× a = 920

a = 0.63 m/s²

hence, the acceleration of submarine is equal to a = 0.63 m/s²

5 0

3 years ago

A billion years ago, Earth and its moon were just 200000 kilometers apart. Express this distance in meters.

Luda [366]

Answer:

The value is $x = 200000000 \ m$

Explanation:

From the question we are told that

The distance between the earth and the moon is $d = 200000 \ km$

Generally ,

$1 \ km = 1000 \ m$

$200000 \ km \to x \ m$

=> $x = \frac{200000 * 1000}{1 }$

=> $x = 200000000 \ m$

4 0

3 years ago

A book with mass 2.3 kg sits on a table. What is the normal force on the

natita [175]

Explanation:

The table is level and there are no other forces on the book, so the normal force is equal to the weight.

N = mg

N = (2.3 kg) (9.8 m/s²)

N = 22.5 N

6 0

3 years ago

Read 2 more answers

A box is pushed horizontally with constant speed across a rough horizontal surface. Which of the following must be true?

Pavel [41]

D

Because if an object is moving at a constant speed the force of friction must equal the applied (horizontal) force, and for it to be accelerating or decelerating, the force of friction and the applied force must be unequal

5 0

3 years ago

A solenoid of length 18 cm consists of closely spaced coils of wire wrapped tightly around a wooden core. The magnetic field str

Kisachek [45]

Answer:

$B_2 = 1.71 mT$

Explanation:

As we know that the magnetic field near the center of solenoid is given as

$B = \frac{\mu_0 N i}{L}$

now we know that initially the length of the solenoid is L = 18 cm and N number of turns are wounded on it

So the magnetic field at the center of the solenoid is 2 mT

now we pulled the coils apart and the length of solenoid is increased as L = 21 cm

so we have

$\frac{B_1}{B_2} = \frac{L_2}{L_1}$

now plug in all values in it

$\frac{2.0 mT}{B_2} = \frac{21}{18}$

$B_2 = 1.71 mT$

3 0

3 years ago