Answer:
a) K = 3 MeV b) K= 1.5 MeV
Explanation:
We can solve this experiment using the equation of the magnetic force with Newton's second law, where the acceleration is centripetal.
F = q v x B
We can also write this equation based on the modules of the vectors
F = qv B sin θ
With Newton's second law
F = ma
F = m v² / r
q v B = m v² / r
v = q B r / m
The kinetic energy is
K = ½ m v²
Substituting
K = ½ m (q B r/ m)²
K = ½ B² r² q² / m
K = (½ B² R²) q²/m
The amount in brackets does not change during the experiment
K = A q² / m
For the proton
K = 3.0 10⁶eV (1.6 10⁻¹⁹ J / 1eV) = 4.8 10⁻¹³ J
With this data we can find the amount we call A
A = K m/q²
A = 4.8 10⁻¹³ 1.67 10⁻²⁷ /(1.6 10⁻¹⁹)²
A = 3.13 10⁻²
With this value we can write the equation
K = 3.13 10⁻² q² / m
Alpha particle
m = 4 uma = 4 1.66 10⁻²⁷ kg
K = 3.13 10⁻² (2 1.6 10⁻¹⁹)² / 4.0 1.66 10⁻²⁷
K = 4.82 10⁻¹³ J ((1 eV / 1.6 10⁻¹⁹ J) = 3 10⁶ eV
K = 3 MeV
Deuteron
K = 3.13 10⁻² (1.6 10⁻¹⁹)²/2 1.66 10⁻²⁷
K = 2.4 10⁻¹³ J (1eV / 1.6 10⁻¹⁹J)
K = 1.5 10⁶ eV
K= 1.5 MeV
Answer:
The pushing force and the skier's mass
(A) is correct option.
Explanation:
Given that,
Mass = 64 kg
Weight = 608 N
Velocity = 21 m/s
Forward force = 45 N
We need to calculate the reaction force of the snow pushing on the skier
Using given data,
The reaction force of the snow pushing on the skier is equal to the pushing force and the skier's mass.
Hence, The pushing force and the skier's mass
(A) is correct option.
Answer:
–8.35 m/s²
Explanation:
We'll begin by converting 104 km/h to m/s. This can be obtained as follow:
3.6 Km/h = 1 m/s
Therefore,
104 km/h = 104 km/h × 1 m/s / 3.6 Km/h
104 km/h = 28.89 m/s
Thus, 104 km/h is equivalent to 28.89 m/s.
Finally, we shall determine the deceleration of the car. This can be obtained as follow:
Initial velocity (u) = 28.89 m/s
Final velocity (v) = 0 m/s
Distance (s) = 50 m
Deceleration (a) =?
v² = u² + 2as
0² = 28.89² + (2 × a × 50)
0 = 834.6321 + 100a
Collect like terms
0 – 834.6321 = 100a
–834.6321 = 100a
Divide both side by 100
a = –834.6321 / 100
a = –8.35 m/s²
Thus, the deceleration of the car is –8.35 m/s².
Answer:
983.400345675 hits per second
Explanation:
Radius = 14.2 cm
Record turn rate = 33 rev/min
Bump separation = 0.499 mm
Circumference of the record = 
Number of bumps in the groove = 
The rate which the bumps hit the stylus = 
The rate at which the bumps hit the stylus 983.400345675 hits per second
Answer: 18.35 m/s
Explanation:
At the highest point of trajectory, the vertical component of the velocity would be zero and the tennis ball would have horizontal component of velocity.
It is given that the initial velocity of the ball is 32 m/s and it makes 35° with the vertical. Hence the horizontal component of the velocity,
v sin θ = 32 m/s × sin 35° = 18.35 m/s
Hence, at the highest point in its trajectory, the tennis ball would be moving with the speed 18.35 m/s.