Answer:
So 240V RMS is equivalent to 339 V peak, or 679 V peak to peak and can be written as 240 Vrms. (the formula is Vrms = Vmax / √2). The waveform is a sinusoid varying about a neutral, which can also be drawn as a vector with a single arrow pointing away from neutral.
Answer:
a) 1321.45 N
b) 1321.45 N
c) 2.66 m/s^2
d) 2.21*10^-22 m/s^2
Explanation:
Hello!
First of all, we need to remember the gravitational law:
![F = G \frac{m_1 m_2}{r^2}](https://tex.z-dn.net/?f=F%20%3D%20G%20%5Cfrac%7Bm_1%20m_2%7D%7Br%5E2%7D)
Were
G = 6.67428*10^-11 N(m/kg)^2
m1 and m2 are the masses of the objects
r is the distance between the objects.
In the present case
m1 = earth's mass = 5.9742*10^24 kg
m2 = 497 kg
r = 1.92 earth radii = 1.92 * (6378140 m) = 1.2246*10^7 m
Replacing all these values on the gravitational law, we get:
F = 1321.45 N
a) and b)
Both bodies will feel a force with the same magnitude 1321.45 N but directed in opposite directions.
The acceleration can be calculated dividing the force by the mass of the object
c)
a_satellite = F/m_satellite = ( 1321.45 N)/(497 kg)
a_satellite = 2.66 m/s^2
d)
a_earth = F/earth's mass = (1321.45 N)/( 5.9742*10^24 kg)
a_earth = 2.21*10^-22 m/s^2
The horizontal force Superman must apply to throw the boulder is 3670N.
According to Newton's Second law of motion,
Force F = Mass m * Acceleration a
We know that Weight W = Mass m * Gravity g
Given,
Weight W = 2400 N
Acceleration a = 15 m/![s^{2}](https://tex.z-dn.net/?f=s%5E%7B2%7D)
Gravitational force g = 9.81 m/![s^{2}](https://tex.z-dn.net/?f=s%5E%7B2%7D)
W = m * g
Mass m = 2400 / 9.81 = 244.65 kg
Horizontal force F = 244.65 * 15 = 3669.7 N
Newton's Second law of motion states that acceleration of an object depends on force acting on the object and mass of the object.
Therefore the horizontal force Superman must apply to throw the boulder is 3670N.
To know more about horizontal force
brainly.com/question/2037071
#SPJ4
Answer:
Explanation:
mass per unit length ρ = .100 / 1.65 = .0606 . kg /m
length of wire L = 1.65 m
For fundamental frequency , the expression is as follows
n = ![\frac{1}{2L} \sqrt{\frac{T}{m} }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2L%7D%20%5Csqrt%7B%5Cfrac%7BT%7D%7Bm%7D%20%7D)
L = 1.65 , T = 16 n and m = .0606
n = ![\frac{1}{2\times 1.65} \sqrt{\frac{16}{.0606} }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%5Ctimes%201.65%7D%20%5Csqrt%7B%5Cfrac%7B16%7D%7B.0606%7D%20%7D)
= 4.9 /s .
This is fundamental frequency .
other mode of vibration ( first three ) will be as follows
4.9 x 2 = 9.8 /s ,
4.9 x 3 = 14.7 /s .
We can solve the problem by using the law of conservation of energy:
- at the beginning, all mechanical energy of the object is just kinetic energy:
, where m is the mass and v is the velocity
- at the point of maximum height, all mechanical energy of the object is just gravitational potential energy:
, where h is the maximum height
Therefore, the conservation of energy becomes:
![\frac{1}{2}mv^2 = mgh](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%3D%20mgh)
Re-arranging, we find the maximum height:
![h=\frac{v^2}{2g} = \frac{(75.0 m/s)^2}{2(9.8 m/s^2)}=287.0 m](https://tex.z-dn.net/?f=h%3D%5Cfrac%7Bv%5E2%7D%7B2g%7D%20%3D%20%5Cfrac%7B%2875.0%20m%2Fs%29%5E2%7D%7B2%289.8%20m%2Fs%5E2%29%7D%3D287.0%20m)