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Step2247 [10]
3 years ago
8

The picture below shows a sprinter at 5 positions. He is initially sitting still on a flat track. He starts running when the sta

rting gun goes off. He travels at constant speed for a few seconds, and then he crosses the finish line and comes to a stop again. The following questions will ask you to describe forces and energies at various points along his path.When would the net force on the sprinter be forward?
Physics
1 answer:
Alika [10]3 years ago
3 0

Answer:

position 2

Explanation:

At position 2, the sprinter started running immediately he heard the sound of the gunshot. This shows that the sprinter accelerated from rest and moved with an increasing acceleration. The magnitude of the final force is higher than the magnitude of the initial force at position 2. Therefore, the difference between the final and initial forces (i.e. net force) is forward (or positive).

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The quantity of heat Q that changes the temperature L1Tof a mass mof a substance isgiven by Q = cmt:T, where c is the specific h
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Answer:

a) Q = 80,000 cal

b) Q = 100,000 cal

c) Q = 540,000 cal

d) Q = 720,000 cal

Explanation:

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Q_{l}  = ML_{f} = 1 * 80

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b) 1 kg of O°C ice water to 1 kg of 100°C boiling water

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c) 1 kg of 100°C boiling water to 1 kg of 100°C steam

Latent heat of vaporization is needed for this conversion

Q_{v} = ML_{v} \\L_{v} = 540 kCal/kg\\Q_{v} =1* 540 \\Q_{v} = 540 kCal = 540000 cal

d)  1 kg of O°C ice to 1 kg of 100°C steam.

Q = Q_{L} + Q_{c} + Q_{v}

Q = 80,000 + 100,000 + 540,000

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7 0
4 years ago
A 3.62 g bullet moving at 270 m/s enters and stops in an initially stationary 2.30 kg wooden block on a horizontal frictionless
scZoUnD [109]
Momentum before collision must be equal to momentum after collision

(m1<span> + m</span>2)v = m1v1<span> + m</span>2v<span>2</span>



3.62g*270 m/s=2.30kg* (x)
convert the units to be the same that is convert the kg mass to grams
1kg=1000g
2.30kg=y
230/100*1000=2300g
3.62*270=2300X
977.4g/m/s=2300X
977.4/2300=0.4250M/S
Finding a velocity after the gun is embedded on the block of wood
3.62*270+2300g*0.425=(3.62+2300)*V
977.5+977.5=2303V
1955=2303V
V=1955/2303
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If you drop an object, it accelerates downward at 9.8 m/s2 (in the absence of air resistance). If, instead, you throw it downwar
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To know more about acceleration refer to: brainly.com/question/14468548

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