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Step2247 [10]
3 years ago
8

The picture below shows a sprinter at 5 positions. He is initially sitting still on a flat track. He starts running when the sta

rting gun goes off. He travels at constant speed for a few seconds, and then he crosses the finish line and comes to a stop again. The following questions will ask you to describe forces and energies at various points along his path.When would the net force on the sprinter be forward?
Physics
1 answer:
Alika [10]3 years ago
3 0

Answer:

position 2

Explanation:

At position 2, the sprinter started running immediately he heard the sound of the gunshot. This shows that the sprinter accelerated from rest and moved with an increasing acceleration. The magnitude of the final force is higher than the magnitude of the initial force at position 2. Therefore, the difference between the final and initial forces (i.e. net force) is forward (or positive).

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How do free-body force diagrams help you determine an object’s direction of motion?
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FBD provides a visual for every force that the object experiences. It can tell you the direction by showing the direction and magnitude of the forces. You can calculate the net force, example being that the applied force is 300N and the force of friction is 100N, the net force is 200N in the direction of the applied force. (Fnet= Fa- Ff).

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Moon rocks resemble rocks from which of the following layers of the earth?
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An unstrained horizontal spring has a length of 0.40 m and a spring constant of 340 N/m. Two small charged objects are attached
Hatshy [7]

Answer:

(a) Both the charges are positive or negative.

(b) Teh value of each charge is 1.53 x 10^-5 C.

Explanation:

Spring constant, K = 340 N/m

Natural length, L = 0.4 m

stretch, y = 0.033 m

(a) Let the charge on each sphere is q and they repel each other so the nature of charge of either sphere may be both positive or both negative.  

(b) The electrostatic force is balanced by the spring force.

\frac{kq^2}{(L + y)^2}=Ky\\\\\\\frac{9\times 10^9 q^2}{(0.4 +0.033)^2} = 340\times0.033\\\\q= 1.53\times 10^{-5} C

6 0
3 years ago
The amount of energy that must be absorbed or lost to raise or lower the temperature of 1 g of liquid water by 1°c _____.
Fiesta28 [93]

Answer:

4.2 J

Explanation:

Specific heat capacity: This is defined as the amount of a heat required to rise a unit mass of a substance through a temperature of 1 K

From specific heat capacity,

Q = cmΔt.............................. Equation 1

Where Q = amount of energy absorbed or lost, c = specific heat capacity of water, m = mass of water, Δt = Temperature rise.

Given: m = 1 g = 0.001 kg, Δt = 1 °C

Constant : c = 4200 J/kg.°C

Substitute into equation 1

Q = 0.001×4200(1)

Q = 4.2 J.

Hence the energy absorbed or lost = 4.2 J

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