1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Step2247 [10]
3 years ago
8

The picture below shows a sprinter at 5 positions. He is initially sitting still on a flat track. He starts running when the sta

rting gun goes off. He travels at constant speed for a few seconds, and then he crosses the finish line and comes to a stop again. The following questions will ask you to describe forces and energies at various points along his path.When would the net force on the sprinter be forward?
Physics
1 answer:
Alika [10]3 years ago
3 0

Answer:

position 2

Explanation:

At position 2, the sprinter started running immediately he heard the sound of the gunshot. This shows that the sprinter accelerated from rest and moved with an increasing acceleration. The magnitude of the final force is higher than the magnitude of the initial force at position 2. Therefore, the difference between the final and initial forces (i.e. net force) is forward (or positive).

You might be interested in
Suppose that a white dwarf is gaining mass through accretion in a binary system. what happens if the mass someday reaches the 1.
Soloha48 [4]
It would blow up turning into a supernova.
7 0
4 years ago
Read 2 more answers
he electronics supply company where you work has two different resistors, R1 and R2, in its inventory, and you must measure the
Paraphin [41]

Answer:

R₁ = 50.77 Ω

Explanation:

Since, we know that:

Electric Power = P = VI

but from Ohm's Law:

V = IR

(or) I = V/R

Therefore,

P = V²/R

(OR) R = V²/P

where,

V = Battery Voltage

R = Resistance of combination

FOR SERIES COMBINATION:

R = Rs = (57 V)²/48 W

Rs = 67.69 Ω

but, we know that:

Rs = R₁ + R₂

R₁ + R₂ = 67.69 Ω

R₁ = 67.69 Ω - R₂  __________ eqn (1)

FOR PARALLEL COMBINATION:

R = Rp = (57 V)²/256 W

Rp = 12.69 Ω

but, we know that:

Rp = (R₁R₂)/(R₁ + R₂) = 12.69 Ω

using eqn (1) and value of R₁ + R₂, we get

Rp = 12.69  = R₂(67.69 - R₂)/67.69

859.08 = 67.69 R₂ - R₂²

R₂² - 67.69 R₂ + 859.08 = 0

Solving this quadratic equation we get the answers:

Either, R₂ = 50.76 Ω

Either, R₂ = 16.92 Ω

Since, it is stated in the question that R₁ > R₂. Therefore, we choose the second value. So,

<u>R₂ = 16.92 Ω</u>

using this value in eqn (1), we get:

R₁ = 67.69 Ω - 16.92 Ω

<u>R₁ = 50.77 Ω</u>

4 0
3 years ago
An 85.0-N crate of apples sits at rest on a ramp that runs from the ground to the bed of a truck. The ramp is inclined at 28.0°
irina [24]

Answer:

A  75.1 N and a direction of 152° to the vertical.

B 85.0 N at 0° to the vertical.

Explanation:

A) The interaction partner of this normal force has what magnitude and direction?

The interaction partner of this normal force is the component of the weight of the crate perpendicular to the ramp. <u>It has a magnitude of 85cos28° = 75.1 N and a direction of 180° - 28° = 152° to the vertical(since it is directed downwards perpendicular to the ramp).</u>

B) The normal and frictional forces are perpendicular components of the contact force exerted on the crate by the ramp. What is the magnitude and direction of the contact force?

Since this force has to balance the weight of the crate, its magnitude is 85.0 N. Its direction has to be vertically opposite to that of the weight.

Since the weight is 180° to the vertical (since it is directed downwards), this force is 0° to the vertical.

<u>So, this force has a magnitude of 85.0 N and a direction of 0° to the vertical.</u>

8 0
3 years ago
A 58 kg skier is going down a 35 degree slope. The areaof each
maxonik [38]

To solve this problem we will use a free body diagram that allows us to determine the Normal Force.

In general, the normal force would be equivalent to

N = mgcos\theta

Since the skier is standing on two skis, his weight will be divide by two

N' = \frac{mgcos\theta}{2}

Pressure is given as the force applied in a given area, that is

P = \frac{F}{A}

Replacing F with N'

P = \frac{N'}{A}

P = \frac{\frac{mgcos\theta}{2}}{A}

Our values are given as,

m = 58kg

g = 9.8m/s^2

\theta = 35\°

A = 0.3m^2

Replacing we have that

P = \frac{\frac{(58)(9.8)cos(35)}{2}}{0.3}

P = 776.01Pa

Therefore the pressure exerted by each ski on the snow is 776.01Pa

6 0
3 years ago
A 1500 W hair dryer operates on a household outlet of 120 V. What is its resistance?
Jlenok [28]

Answer:

I literally just got done doing something like this in my physic class. The resistance is 9.6 ohms.

5 0
4 years ago
Other questions:
  • If 50 mL of each of the liquids in the answer choices were poured into a 250 mL beaker, which layer would be directly above a sm
    8·1 answer
  • Newton’s Second Law of motion defines force in terms of mass and acceleration, F= ma. Which of the following is false? The term
    12·1 answer
  • A sound wave has a speed of 343 m/s in air. What is the wavelength of a sound wave with a frequency of 686 Hz
    11·1 answer
  • If a project team decided that a drugstore would earn the LT Credit—LEED for Neighborhood Development Location, what other Locat
    9·1 answer
  • A slingshot fires a pebble from the top of a building at a speed of 16.0 m/s. The building is 27.0 m tall. Ignoring air resistan
    14·1 answer
  • Calculate the heat flux (in W/m^2) through a sheet of a metal 14 mm thick if the temperatures at the two faces are 350 and 140°C
    15·1 answer
  • If you carry out an experiment measuring the weight and mass of objects in one particular location on the earth, what relation w
    12·2 answers
  • Evaluate u+xy where U=3 X=4 Y=7
    13·1 answer
  • Water initially at 200 kPa and 300°C is contained in a piston–cylinder device fitted with stops. The water is allowed to cool at
    12·1 answer
  • Brainliest!!! Write: Forces are all around us. Imagine that your teacher has asked you to teach a lesson to your peers about for
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!