C) the moon does not have a strong magnetic field
Answer:
d. 5 ohms
Explanation:
For resistors in parallel, the equivalent resistance is found with:
1/Req = ∑(1/R)
1/R = 1/15 + 1/15 + 1/15
1/R = 3/15
R = 15/3
R = 5
Answer:
Energy
A wave is a disturbance that carries energy from one place to another through matter and space.
Explanation:
A wave can be defined as a form of disturbance that carries energy from one place to another through matter and space.
The energy of wave depends on the frequency of the wave and the wavelength (lambda) of that particular wave.
Mathematically,
V = f × lambda
Answer:
a) When R is very small R << r, therefore the term R+ r will equal r and the current becomes
b) When R is very large, R >> r, therefore the term R+ r will equal R and the current becomes
Explanation:
<u>Solution :</u>
(a) We want to get the consumed power P when R is very small. The resistor in the circuit consumed the power from this battery. In this case, the current I is leaving the source at the higher-potential terminal and the energy is being delivered to the external circuit where the rate (power) of this transfer is given by equation in the next form
P=∈*I-I^2*r (1)
Where the term ∈*I is the rate at which work is done by the battery and the term I^2*r is the rate at which electrical energy is dissipated in the internal resistance of the battery. The current in the circuit depends on the internal resistance r and we can apply equation to get the current by
I=∈/R+r (2)
When R is very small R << r, therefore the term R+ r will equal r and the current becomes
I= ∈/r
Now let us plug this expression of I into equation (1) to get the consumed power
P=∈*I-I^2*r
=I(∈-I*r)
=0
The consumed power when R is very small is zero
(b) When R is very large, R >> r, therefore the term R+ r will equal R and the current becomes
I=∈/R
The dissipated power due toll could be calculated by using equation.
P=I^2*r (3)
Now let us plug the expression of I into equation (3) to get P
P=I^2*R=(∈/R)^2*R
=∈^2/R
Answer:
(a) Kav Ne = Kav Kr = 7.29x10⁻²¹J
(b) v(rms) Ne= 659.6m/s and v(rms) Kr= 323.7m/s
Explanation:
(a) According to the kinetic theory of gases the average kinetic energy of the gases can be calculated by:
(1)
<em>where 
: is the kinetic energy, k: Boltzmann constant = 1.38x10⁻²³J/K, and T: is the temperature </em>
<u>From equation (1), we can calculate the</u><u> average kinetic energies for the krypton and the neon:</u>
(b) The rms speeds of the gases can be calculated by:
<em>where m: is the mass of the gases and 
: is the root mean square speed of the gases</em>
For the neon:
For the krypton:
Have a nice day!
