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3 years ago

A clothes dryer uses about 4 amps of current from a 240 volt line. How much power does it use?

Physics

1 answer:

Nimfa-mama [501]3 years ago

6 0

Answer: 960 W

Explanation:

Power is the rate at which energy is dispensed. Electrical power can be defined as the rate at which electric energy is flowing in an electric circuit. It is given by the formula:

P = V I

Where, V is the voltage(V) , I is the current (A).

V = 240 V (given)

I = 4 A (given)

P = VI = 960 Watts

Hence, power used by the cloth dryer is 960 W.

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You are on the roof of the physics building, 46.0 above the ground . Your physics professor, who is 1.80 tall, is walking alongs

Fudgin [204]

Answer:

3.6m

Explanation:

if you are at a building that is 46m above the ground, and the professor is 1.80m, the egg must fall:

46m - 1.80m = 44.2m

the egg must fall for 44.2m to land on the head of the professor.

Now, how many time this takes?

we have to use the following free fall equation:

$h=v_{0}t+\frac{1}{2}gt^2$

where $h$ is the height, $v_{0}$ is the initial velocity, in this case $v_{0}=0$ . $g$ is the acceleration of gravity: $g=9.81m/s$ and $t$ is time, thus:

$h=\frac{1}{2}gt^2$

clearing for time:

$2h=gt^2\\\frac{2h}{g}=t^2\\\sqrt{\frac{2h}{g}} =t$

we know that the egg has to fall for 44.2m, so $h=44.2$ , and $g=9.81m/s$ , so we the time is:

$t=\sqrt{\frac{2(44.2m)}{9.8m/s^2} }=\sqrt{\frac{88.4m}{9.81m/s^2} } =\sqrt{9.011s^2}= 3.002s$

Finally, if the professor has a speed of $v=1.2m/s$ , it has to be at a distance:

$d=vt$

and t=3.002s:

$d=(1.2m/s)(3.002s)=3.6m$

so the answer is the professor has to be 3.6m far from the building when you release the egg

7 0

3 years ago

By means of a rope whose mass is negligible, two blocks are suspended over a pulley, as the drawing shows, with m1 = 12.1 kg and

puteri [66]

Answer:

14.8 kg

Explanation:

We are given that

$m_1=43.7 kg$

$m_2=12.1 kg$

$g=9.8 m/s^2$

$a=\frac{1}{2}(9.8)=4.9 m/s^2$

We have to find the mass of the pulley.

According to question

$T_2-m_2 g=m_2 a$

$T_2=m_2a+m_2g=m_2(a+g)=12.1(9.8+4.9)=177.87 N$

$T_1=m_1(g-a)=43.7(9.8-4.9)=214.13 N$

Moment of inertia of pulley= $I=\frac{1}{2}Mr^2$

$(T_2-T_1)r=I(-\alpha)=\frac{1}{2}Mr^2(\frac{-a}{r})=\frac{1}{2}Mr(-4.9)$

Where $\alpha=\frac{a}{r}$

$(177.87-214.13)=-\frac{1}{2}(4.9)M$

$-36.26=-\frac{1}{2}(4.9)M$

$M=\frac{36.26\times 2}{4.9}=14.8 kg$

Hence, the mass of the pulley=14.8 kg

6 0

3 years ago

Identify the stages of the water cycle where water moves downward from the force of gravity

hoa [83]

Umm I think that it's called a run off! Because it's running off of a surface into water.

8 0

3 years ago

Read 2 more answers

which statement tells you where the metalloids are located in the periodic table A.metalloids are the elements to the left of th

IceJOKER [234]

Were is the table at?

5 0

4 years ago

A boy on a swing set has a speed of 4.5 m/s and a centripetal acceleration of 8.1 m/s2 at the bottom of his swing. How long are

EleoNora [17]

Answer:

R = 1.8 m

Explanation:

This is a simple harmonic movement exercise, at the bottom of the swing the acceleration is vertical upwards and the speed is tangential to the trajectory, that is horizontal; the expression for the centralized acceleration is

$a_{c}$ = v² / R

R = v² /a_{c}

where the radius is equal to the length of the swing

let's calculate

R = 8.1 / 4.5

R = 1.8 m

5 0

3 years ago