Answer : The change in molar entropy of the sample is 10.651 J/K.mol
Explanation :
To calculate the change in molar entropy we use the formula:
where,
= change in molar entropy
n = number of moles = 1.0 mol
= final temperature = 300 K
= initial temperature = 273 K
= heat capacity of chloroform = 
Now put all the given values in the above formula, we get:
![\Delta S=1.0\times [91.47\ln T+7.5\times 10^{-2}T]^{300}_{273}](https://tex.z-dn.net/?f=%5CDelta%20S%3D1.0%5Ctimes%20%5B91.47%5Cln%20T%2B7.5%5Ctimes%2010%5E%7B-2%7DT%5D%5E%7B300%7D_%7B273%7D)
Therefore, the change in molar entropy of the sample is 10.651 J/K.mol
Answer:
Mass = 13.14 g
Explanation:
Given data:
Mass of zinc = 11.89 g
Mass of HCl needed = ?
Solution:
Chemical equation:
Zn + 2HCl → ZnCl₂ + H₂
Number of moles of Zn:
Number of moles = mass/molar mass
Number of moles = 11.89 g/ 65.38 g/mol
Number of moles = 0.18 mol
Now we will compare the moles of Zn and HCl.
Zn : HCl
1 : 2
0.18 : 2/1×0.18 = 0.36 mol
Mass of HCl:
Mass = number of moles × molar mass
Mass = 0.36 mol ×36.5 g/mol
Mass = 13.14 g
Answer:
So on dissolution, it will produce magnesium hydroxide which is a base and the solution will be basic in nature. So it will change the color of red litmus paper to blue, and blue will remain the same.
Explanation:
Answer:
5.90
Explanation:
Initial moles of CH3COO- = 10.0/1000 x 0.75 = 0.0075 mol
Moles of HCl added = 5.0/1000 x 0.10 = 0.0005 mol
CH3COO- + HCl => CH3COOH + Cl-
Moles of CH3COO- left = 0.0075 - 0.0005 = 0.007 mol
Moles of CH3COOH formed = moles of HCl added = 0.0005 mol
pH = pKa + log([CH3COO-]/[CH3COOH])
= -log Ka + log(moles of CH3COO-/moles of CH3COOH)
= -log(1.78 x 10^(-5)) + log(0.007/0.0005)
= 5.90
Answer:
Si14- Si^4+
As33- As^3-
Mg12- Mg^2+
Rb37- Rb^+
F9- F^-
Ge32- Ge^4+
Sn50- Sn^2+, Sn^4+
Explanation:
The elements shown in the answer have their common ions written beside them.
Silicon mostly forms positive ions in oxyacids and complex ions. Arsenic mostly forms its anion. Magnesium forms only the +2cation just as rubidium only forms the +1 cation. The fluoride ion is F^- while tin may for a +2*or +4 cation. Germanium usually forms the +4 cation.
