Answer:
The correct answers are C and D.
<h3>
Answer:</h3>
147.05 g/mol
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
CuClO₃
<u>Step 2: Find MM</u>
Molar Mass of Cu - 63.55 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of CuClO₃ - 63.55 + 35.45 + 3(16.00) = 147.05 g/mol
An example of a land form from magma is B. Lava Plateau.
Answer:
2.79 mg iron-59 is left in the sample after 267 days.
Explanation:
Given that:
Half life = 44.5 days
Where, k is rate constant
So,
The rate constant, k = 0.0156 days⁻¹
Using integrated rate law for first order kinetics as:
Where,
is the concentration at time t
is the initial concentration = 180 mg
Time = 267 days
So,
<u>2.79 mg iron-59 is left in the sample after 267 days.</u>