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2 years ago

PLEASE HELP DUE IN 1 HOUR

Chemistry

1 answer:

NARA [144]2 years ago

8 0

Answer:

All the carbon will combust with atmospheric oxygen to form carbon dioxide. This means that the charcoal present will become consumed to form colorless carbon dioxide gas.

Explanation:

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Good morning, I have a question..

matrenka [14]

Answer:

<h3>The answer is 5.24 mL</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question

mass = 152 g

density = 29 g/cm³

We have

$volume = \frac{152}{29} \\ = 5.24137931...$

We have the final answer as

Hope this helps you

7 0

3 years ago

A container with 3.0 moles of gas has a volume of 60.0L with a temperature at 400.K what is the pressure

iris [78.8K]

Answer: P= 1.64 atm

Explanation: solution attached.

Use Ideal gas law

PV= nRT

Derive for P

P= nRT/V R= 0.08205 L.atm/mol.K

Substitute the values.

3 0

3 years ago

(55 points) Please help me with my homework please please help me thanks so much

balandron [24]

Answer:

I didn't do the observation so I can't help sorry

8 0

2 years ago

I need help on dis chem shi if y’all can answer fa me I would appreciate dat

elena55 [62]

I think it’s A I’m not 100% sure but I mean it’s worth a try

3 0

3 years ago

A chemist must prepare 800.0mL of sodium hydroxide solution with a pH of 12.10 at 25°C. She will do this in three steps: Fill a

AnnZ [28]

Answer:

0.42 g

Explanation:

pH = 12.10 (25 °C)

V = 800.0 mL = 0.800 L

To find the mass of sodium hydroxide (NaOH) we can use the pH:

$14 = pH + pOH$

$pOH = 14 - pH = 14 - 12.10 = 1.90$

$pOH = -log ([OH^{-}])$

$[OH]^{-} = 10^{-pOH} = 10^{-1.90} = 0.013 M$

Now, we can find the number of moles (η) of OH:

$\eta = ([OH]^{-})*V = 0.013 mol/L * 0.800 L = 1.04 \cdot 10^{-2} moles$

Since we have 1 mol of OH in 1 mol of NaOH, the number of moles of NaOH is equal to 1.04x10⁻² moles.

Finally, with the number of moles we can find the mass of NaOH:

$m = \eta * M$

<em>Where M is the molar mass of NaOH = 39.9 g/mol </em>

$m = 1.04 \cdot 10^{-2} moles * 39.9 g/mol = 0.42 g$

Therefore, the mass of sodium hydroxide that the chemist must weigh out in the second step is 0.42 g.

I hope it helps you!

3 0

3 years ago