Ask question

Ask question

All categories

3 years ago

13

Determine how many formula units are in 2.35 moles of lithium phosphite?

1 answer:

Stells [14]3 years ago

4 0

Answer:

Determine how many formula units are in 2.35 moles of lithium phosphite?

Explanation:

After reading the sources provided write a 250 word summary on the contributions of West Virginians to the war effort.What are the dimensions of the product? 2 6 4 1 -3 0 x -3 -2 -8 2 3 5 1 x 2 2 x 2 3 x 2 3 x 3Can somebody help me with this pleaseDetermine how many formula units are in 2.35 moles of lithium phosphite?Can someone help? It's due todayWhat main idea links all three of the article excerpts contained in th passage together? A) Taxation rates should be applied equally and fairly to all people. B A little bit of kindness goes a long way in trying to change the world. C) No one deserves to be lonely, and everyone deserves to be loved. D African-Americans had to fight long and hard to receive equal rights in America.Can somebody help me with this pleaseCan somebody help me with this pleaseAfter reading the sources provided write a 250 word summary on the contributions of West Virginians to the war effort.

You might be interested in

Which of these is an example of a physical change ?

Gre4nikov [31]

It's 1. Melting a substance. The rest are chemical changes

8 0

3 years ago

What could you change or add to your models based on what you have learned about molecules and phases so far?

timurjin [86]

Answer:Phase changes require either the addition of heat energy (melting, evaporation, and sublimation) or subtraction of heat energy (condensation and freezing). ... Changing the amount of heat energy usually causes a temperature change.

Explanation:

5 0

2 years ago

Read 2 more answers

A 100. 0 ml sample of 0. 10 m nh3 is titrated with 0. 10 m hno3. Determine the ph of the solution after the addition of 100. 0 m

DerKrebs [107]

The pH of the solution after the addition of 100. 0 ml of HNO3. The kb of NH3 is 1. 8 × 10-5. So, pH is 10.9 basic .

This neutralization occurs as the acid is added to the base:

NH3(aq)+ HNO3(aq)= NH4NO3(aq)+ H2O(l)

The initial moles of NH3present is given by,

nNH3= c×v= 0.10× 100/1000= 0.01m

The number of moles of

HNO3 added is given by:

nHNO3= c×v= 0.10× 100/1000= 0.001

It is clear from the equation that the acid and base react in a 1:1 molar ratio. So, the no. moles of NH3remaining will be 0.01 - 0.001= 0.009

The total volume is now

100.0+100.0= 200.0x cm3

The concentration of NH3 is given by,

[NH3]= c/v= 0.001/200/1000= 0.05x mol/l .

pOH= 12 (pKb− logb)

where b is the base's concentration.

Given that there is little dissociation, we can roughly compare this to the starting concentration.

pKb= −logKb= −log(1.8×10−5)= 4.744

pOH= 3.056

At 25∘xC, we know that, pH+ pOH=14

pH= 14− 3.056= 10.9

To know more about Equilbrium, visit-brainly.com/question/14366127

#SPJ4

8 0

1 year ago

What type of reaction is shown in the following chemical equation in NH3+HC1 NH4C1

natulia [17]

Explanation:

combination reaction

3 0

2 years ago

Read 2 more answers

A certain metal M forms a soluble sulfate salt MSO, Suppose the left half cell of a galvanic cell apparatus is filled with a 3.0

bija089 [108]

Answer:

E = 0.062 V

Explanation:

(a) See the attached file for the answer

(b)

Calculating the voltage (E) using the formula;

E = - (2.303RT/nf)log Cathode/Anode

Where,

R = 8.314 J/K/mol

T = 35°C = 308 K

F- Faraday's constant = 96500 C/mol,

n = number of moles of electron = 2

Substituting, we have

E = -(2.303 * 8.314 *308/2*96500) *log (0.03/3)

= -0.031 * -2

= 0.062V

Therefore, the voltmeter will show a voltage of 0.062 V

5 0

2 years ago