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ella [17]
4 years ago
5

A compound machine is made up of one simple machine True or False

Physics
2 answers:
Ne4ueva [31]4 years ago
6 0
True is the answer I believe so
kherson [118]4 years ago
5 0

the statement is false. Compound machines are made up of two or more simple machines  

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An element's atomic number is 34. How many protons would an atom of this element have?
Elena-2011 [213]

34. The element would have 34 protons. Also 34 electrons.

7 0
3 years ago
What is the mass in grams of 5.50 × 1014 lead (pb) atoms?
olchik [2.2K]
There will be no way that to happen aton is a positive charge
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3 years ago
PLEASEEEEEEEE HELPPPPPPP
OlgaM077 [116]

Answer:  62.25

Explanation: F = ma

F = 7.5 * 8.3

F = 62.25

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6 0
3 years ago
A small segment of wire contains 10 nC of charge. The segment is shrunk to one-third of its original length. A proton is very fa
Alik [6]

To solve this problem we will apply the concepts related to the electric field, linear charge density and electrostatic force.

The electric field is

E = \frac{\lambda}{2\pi \epsilon_0 r}

Here,

\lambda= Linear charge density

\epsilon_0 = Permittivity of free space

r = Distance

The linear charge density can be written as,

Linear charge density is given as

\lambda = \frac{q}{L}

Replacing,

E = \frac{\frac{q}{L}}{2\pi \epsilon_0 r}

E = \frac{q}{2\pi \epsilon_0 rL}

The initial and final electric Force can be written as function of the charge and the electric field as

F_i = E_i q

F_f = E_f q

If we replace the value for the electric field we have,

F_i = (\frac{q}{2\pi \epsilon_0 rL})q = (\frac{q^2}{2\pi \epsilon_0 rL})

Length is one third at the end, then

F_f = (\frac{q}{2\pi \epsilon_0 r(L/3)})q = (\frac{3q^2}{2\pi \epsilon_0 rL})

The ratio of the force is

\frac{F_f}{F_i} = \frac{(\frac{3q^2}{2\pi \epsilon_0 rL})}{(\frac{q^2}{2\pi \epsilon_0 rL})}

\frac{F_f}{F_i} = 3

Therefore the required ratio is 3

7 0
3 years ago
What is t=3seconds in scrience
alekssr [168]
Well....t usually stands for time and the unit seconds proves that
8 0
3 years ago
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