The work done is 
Work Done = Change in Kinetic Energy (ΔKE)
<u>Explanation</u>
In first 1 hour it travels 72 km
So, Velocity = 
or, Initial Velocity (u) = 20 m/s
Similarly for the next hour it covers 90 km
So, Velocity = 
or, Final Velocity (v) = 20 m/s
Work done = Change in Kinetic Energy (ΔKE)
Work done = ΔKE = 
ΔKE = 
= 
= 281250 joule
=
Answer:
Vx' = (Vx - u) / (1 - Vx *u / c^2) velocity transformation formula
In both cases we wish to measure the velocity in the frame of the earth which is moving at speed u = -.99 c relative to the spaceship
VA' = (c + .99c) / (1 - (-.99 c * c) / c^2) = 1.99c / 1.99 = c
VB' = (-c + .99c) / (1 - (-c * -.99c) / c^2) = .01 c / .01 = c
In both cases an observer on earth will observe the light traveling at speed c.
Answer:
The outside of a neuron has more sodium ions while at resting state. When a electrical signal is going to pass through, the sodium channels open up first and the positive sodium ions rush inward making the inner side more positive. This is called action potential.
There is layer of fatty substances called as Myelin Sheath over the course of axons. It helps the electrical signal to be transmitted with a fast pace and efficiently over the course.
The edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.
<h3>Volume of molybdenum</h3>
V = (zm/ρN)
where;
- z is 2 for cubic unit cell
- m is mass of the molybdenum
- ρ is density of the molybdenum
V = (2 x 95.96) / (10.28 x 6.02 x 10²³)
V = 3.10 x 10⁻²³ cm³
<h3>Edge length of the unit cell</h3>
a³ = V
a = (V)^¹/₃
a = ( 3.10 x 10⁻²³)^¹/₃
a = 3.142 x 10⁻⁸ cm
a = 3.142 x 10⁻¹⁰ m
a = 314.2 x 10⁻¹² m
a = 314.2 pm
Thus, the edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.
Learn more about edge length here:
brainly.com/question/16673486
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Answer:
should be d because friction allows things to go faster or slower
