1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
makvit [3.9K]
4 years ago
6

The substance nitrogen has the following properties: normal melting point: 63.2 K normal boiling point: 77.4 K triple point: 0.1

27 atm, 63.1 K critical point: 33.5 atm, 126.0 K At temperatures above 126 K and pressures above 33.5 atm, N2 is a supercritical fluid . N2 does not exist as a liquid at pressures below atm. N2 is a _________ at 16.7 atm and 56.5 K. N2 is a _________ at 1.00 atm and 73.9 K. N2 is a _________ at 0.127 atm and 84.0 K.
Chemistry
1 answer:
shusha [124]4 years ago
3 0

Answer:

- N2 does not exist as a liquid at pressures below 0.127 atm.

- N2 is a solid at 16.7 atm and 56.5 K.

- N2 is a liquid at 1.00 atm and 73.9 K

- N2 is a gas at 0.127 atm and 84.0 K.

Explanation:

Hello,

At first, we organize the information:

- Normal melting point: 63.2 K.

- Normal boiling point: 77.4 K.

- Triple point: 0.127 atm and 63.1 K.

- Critical point: 33.5 atm and 126.0 K.

In such a way:

- N2 does not exist as a liquid at pressures below 0.127 atm: that is because below this point, solid N2 exists only (triple point).

- N2 is a solid at 16.7 atm and 56.5 K: that is because it is above the triple point, below the critical point and below the normal melting point.

- N2 is a liquid at 1.00 atm and 73.9 K: that is because it is above the triple point, below the critical point and below the normal boiling point.

- N2 is a gas at 0.127 atm and 84.0 K: that is because it is above the triple point temperature at the triple point pressure.

Best regards.

You might be interested in
Container A holds 717 mL of an ideal gas at 2.80 atm. Container B holds 174 mL of a different ideal gas at 4.30 atm. Container A
horsena [70]

Answer:

3.09 atm

Explanation:

Given that:

Volume of container A = 717 mL

Pressure of container A = 2.80 atm

Volume of container B = 174 mL

Pressure of container B = 4.30 atm

Now, if the valve are being removed and the gases are allowed to mix together; then

The total final pressure can be calculated by using the formula:

P_f = \dfrac{P_AVA+P_BV_B}{V_A+V_B}

P_f = \dfrac{2.80*717+4.30*174}{717+174}

P_f = \dfrac{2007.6+748.2}{891}

P_f = \dfrac{2755.8}{891}

\mathbf{P_f =3.09 \ atm}

4 0
3 years ago
Choose all the answers that apply. Which of the following is true about the sun's radiation?
yawa3891 [41]
B. It is shortwave.....
7 0
3 years ago
Read 2 more answers
Rank the following chemical species from largest ionic radius to smallest ionic radius
7nadin3 [17]

Answer:

Biggest Radii     V²⁺ > V³⁺ > V⁴⁺ > V⁵⁺     Smallest Radii

General Formulas and Concepts:

  • Periodic Trends: Atomic/Ionic Radii
  • Coulomb's Law

Explanation:

The Periodic Trend for Atomic Radii is down and to the left. Therefore, the element with the largest radius would be in the bottom left corner of the Periodic Table.

Anions will always have a bigger radii than the parent radii. When we add e⁻ to the element, we are increasing the e⁻/e⁻ repulsions. This will cause e⁻ to repel themselves more and thus create more space, increasing the radii size.

Cations will always have smaller radii than the parent radii. When we remove e⁻ from the element, we are decreasing e⁻/e⁻ repulsions. Since there are less e⁻, there is no need for more space and thus decreases the radii size.

Since Cations are smaller than the parent radii, the more e⁻ we remove, the smaller it will become.

Therefore, the least removed e⁻ Vanadium would be the largest and the most removed e⁻ Vanadium would be the smallest.

4 0
3 years ago
Given that E°red = -1.66 V for Al3+/ Al at 25°C, find E° and E for the concentration cell expressed using shorthand notation bel
lbvjy [14]

Answer:

E° = 0.00 V

E = 0.079 V

Explanation:

We can identify both half-reactions occurring in a concentration cell.

Anode (oxidation): Al(s) → Al³⁺(1.0 × 10⁻⁵ M) + 3 e⁻   E°red = -1.66 V

Cathode (reduction): Al³⁺(0.100 M) + 3 e⁻ → Al(s)     E°red = -1.66 V

The global reaction is:

Al(s) + Al³⁺(0.100 M) → Al³⁺(1.0 × 10⁻⁵ M) + Al(s)

The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E° = E°red, cat - E°red, an = -1.66 V - (-1.66 V) = 0.00 V

To calculate the cell potential (E) we have to use the Nernst equation.

E = E° - (0.05916/n) .log Q

where,

n: moles of electrons transferred

Q: reaction quotient

E = 0.00 V - (0.05916/3) .log (1.0 × 10⁻⁵/0.100)

E = 0.079 V

4 0
3 years ago
PLEASE NO GUESSES OR INCORRECT ANSWERS
sertanlavr [38]
Diffusion is the movement of any chemical from one place to another. 
Osmosis is the movement of water across a partially permeable membrane.


I hope this helps!
3 0
4 years ago
Other questions:
  • From its position in the periodic table, one would predict that the element potassium has the following property: a. more active
    10·2 answers
  • A series of lines involving a common level in the spectrum of atomic hydrogen lies at 656.46 nm, 486.27 nm, 434.17 nm, and 410.2
    14·1 answer
  • Water supplies are often treated with chlorine as one of the processing steps in treating wastewater. Estimate the liquid diffus
    7·2 answers
  • Which statement correctly identifies a transfer of energy within Earth’s atmosphere?
    7·1 answer
  • Which of the following are examples of potential energy
    12·2 answers
  • Why is DNA called a double helix?
    5·1 answer
  • Use scientific notation to solve
    13·1 answer
  • 4. (08.01 MC)
    14·1 answer
  • Finish the essay technology improves nursing
    5·1 answer
  • How does sublimation occur and why does it not pass through the liquid phase?​
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!