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ANTONII [103]
3 years ago
14

A material was cooled from 100°C to 40°C. What is the temperature change?

Chemistry
1 answer:
vazorg [7]3 years ago
8 0
The answers D) -60
Just subtract
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For which of the following reactions is S° > 0. Choose all that apply. N2(g) + 3H2(g) 2NH3(g) 2C2H6(g) + 7O2(g) 4CO2(g) + 6H2
Lostsunrise [7]

Answer: 2C_2H_6(g)+7O_2(g)\rightarrow 4CO_2(g)+6H_2O(g)

NH_4I(s)\rightarrow NH_3(g)+HI(g)

2H_2O(g)+2SO_2(g)\rightarrow 2H_2S(g)+3O_2(g)

Explanation:

Entropy is the measure of randomness or disorder of a system.

A system has positive value of entropy if the disorder increases and a system has negative value of entropy if the disorder decreases.

1. N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

As 4 moles of gaseous reactants are changing to 2 moles of gaseous products,  the randomness is decreasing and the entropy is negative

2. 2C_2H_6(g)+7O_2(g)\rightarrow 4CO_2(g)+6H_2O(g)

As 9 moles of gaseous reactants are changing to 10 moles of gaseous products,  the randomness is increasing and the entropy is positive.

3. NH_4I(s)\rightarrow NH_3(g)+HI(g)

As 1 mole of solid reactants is changing to 2 moles of gaseous products, the randomness is increasing and the entropy is positive.

4. 2H_2O(g)+2SO_2(g)\rightarrow 2H_2S(g)+3O_2(g)

As 4 moles of gaseous reactants is changing to 5 moles of gaseous products, the randomness is increasing and the entropy is positive

5. 2NO(g)+2H_2(g)\rightarrow N_2(g)+2H_2O(l)

As 4 moles of gaseous reactants is changing to 1 moles of gaseous products, the randomness is decreasing and the entropy is negative.

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Question 19-20<br> I’m not really sure, can someone help me
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Hi my name is Jaleesa The answer = -1
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Which nonmetal would an ion of Ca2+ MOST LIKELY ionically bond with in a 1:1 ratio? A) one atom of neon B) one atom of carbon C)
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Ca2+ would bond to any element in a 1 to 1 ratio that had an equal and opposite charge.

Neon is a noble gas, and doesn’t form bonds m

Carbon isn’t typically found in ion state, but if it did, it would likely by C4+

Flouring in ionic state is F1-, so you would need 2 flourines to cancel the 2+ charge of Calcium

Then the only option left would be Oxygen which, when in ion form is found be 2-
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