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saw5 [17]
3 years ago
8

NEED HELP ASAP!! (15 points)

Mathematics
1 answer:
LiRa [457]3 years ago
3 0

Answer:

Step-by-step explanation:

a b c

13 10 z

169 100 z 269 16.4      hope this help's

 

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1. In the diagram below, a large flagpole stands outside of an office
Snowcat [4.5K]

Answer:

Step-by-step explanation:

Let h bet the height of the building.

Mark is 60+310 = 370 m from building.

35/60 = h/370

h = 1295/6 = 215⅚ meters

8 0
3 years ago
PLS HELP IM DESPARET
vesna_86 [32]

Answer:

19/4 or 4.75

Step-by-step explanation:

Week 1: 1 1/8 = 1.125

Week 2: -2 5/8 = -2.625*

Week 3: 1 3/4 = 1.75

Week 4: -1 1/2 = -1.5

Week 5: 2 1/8 = 2.125*

2 1/8 - (-2 5/8) = 2.125 - (-2.625)

19/4 or 4.75

3 0
3 years ago
Simplify. (2/5)^4... words to fill in minimum space
Stella [2.4K]
When you have a power to a fraction, you simply take it by the top and then by the bottm.

So, split it into two: (2)^4 and (5)^4

Solve: (2)^4=16
(5)^4=625

So the fraction is: 16/625

Check to see if it reduces: It doesn't. (Odd and even numbers that have no common multiples).

Therefore, that's the answer.
3 0
3 years ago
7
Fofino [41]

Answer:

15:7

Step-by-step explanation:

you put the numbers in order first the number of on time trains to off time trains

5 0
1 year ago
Determine whether the series is convergent or divergent.
elixir [45]

Answer:

Step-by-step explanation:

Test for convergence or divergence of a series using Comparison test

Function.

Σ Sin(1/n). From n= 1 to n=∞

Comparison test states that

Let, 0 ≤ an ≤ bn

For all n

Then, if

Σbn converges then, Σan converge

Σan diverges then, Σbn diverge

I.e if the small series diverges, then, the big series diverges and if the big series converges then, the small series converges.

Let compare the given function to 1/n

1/n is greater than Sin(1/n)

0 ≤ Sin(1/n) ≤ 1/n

1/n is a positive number and it is always greater than 1.

We know that 1/n diverse from p series

P series says that,

Σ 1/n^p

If p≤1 then the series diverges

If p>1 the series converges

So when we compare this to 1/n, then p is equal to 1, therefore, the series diverges.

Now, comparing this to the comparison thereom

Since, the large series bn diverges, then the smaller series an diverges.

Then,

Σ 1 / n diverges implies that.

Σ Sin(1/n) diverges too

5 0
3 years ago
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