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3 years ago

What is the chemical formula for acetone

Chemistry

2 answers:

GenaCL600 [577]3 years ago

8 0

Answer:

C3H6O

Explanation:

Len [333]3 years ago

5 0

Answer:

The chemical formula for acetone is CH3COCH3 and its condensed formula is C3H6O.

Let me know if you need any other help:)

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Balance the following redox reaction by inserting the appropriate coefficients. SO4^2- + NH3 = SO3^2- + H2O + N2

Harlamova29_29 [7]

SO₄²⁻ +NH₃ → SO₃²⁻ + H₂O +N₂

The balanced of the above redox reaction is as below

3SO₄²⁻ + 2NH₃ → 3SO₃²⁻ + 3 H₂O + N₂

Explanation

According to the law of mass conservation the number of atoms in the reactant side must be equal to number of atoms in product side.

Inserting coefficient 3 in front of SO₄² , 2 in front of NH₃, 3 in front of SO₃²⁻ and 3 in front of H₂O balance the equation above. This is because the number of atoms are equal in both side.

for example there are 2 atoms of N in both side of the reaction.

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3 years ago

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What do two or more atoms form when they share electrons in a chemical bond

dlinn [17]

A covalent bond is your answer

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3 years ago

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When a 3.25 g sample of solid sodium hydroxide was dissolved in a calorimeter in 100.0 g of water, the temperature rose from 23.

sertanlavr [38]

Answer : The enthalpy change for the solution is 42.8 kJ/mol

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m\times c_2\times \Delta T]$

where,

q = heat released by the reaction

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the water

$c_1$ = specific heat of calorimeter = $15.8J/^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m$ = mass of water = 100.0 g

$\Delta T$ = change in temperature = $T_2-T_1=(32.0-23.9)=8.1^oC$

Now put all the given values in the above formula, we get:

$q=[(15.8J/^oC\times 8.1^oC)+(100.0g\times 4.18J/g^oC\times 8.1^oC)]$

$q=3513.8J=3.5138kJ$ (1 kJ = 1000 J)

Now we have to calculate the enthalpy change for the solution.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat released = 3.5138 kJ

m = mass of NaOH = 3.25 g

Molar mass of NaOH = 40 g/mole

$\text{Moles of }NaOH=\frac{\text{Mass of }NaOH}{\text{Molar mass of }NaOH}=\frac{3.25g}{40g/mole}=0.0812mole$

Now,

$\Delta H=\frac{3.5138kJ}{0.0821mole}=42.8kJ/mol$

Therefore, the enthalpy change for the solution is 42.8 kJ/mol

4 0

3 years ago

How is the amount of available sunlight most likely to affect the makeup of an ecosystem

Debora [2.8K]

Answer:

C. it will have more photosynthesis if it gets more sunlight

Explanation:

The amount of sunlight is crucial for what kind of an ecosystem will develop. This is because the sunlight is what enables the development of the producer communities. The producers use the sunlight in order to perform photosynthesis, so the more sunlight there is, the more photosynthesis they will perform. If there is lot of sunlight, then there will be an abundance of producers in the ecosystem, and since they are the basis of any ecosystem, there will be lot of consumers as well, thus the ecosystem will have an abundance of species from every trophic level.

8 0

3 years ago

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A 3.0 L cointainer contains 4 mol He, 2 mol Ne,and 1 mol Ar. What is the mole fraction of neon gas? What is the partial pressure

CaHeK987 [17]

Answer:

Partial pressure of Ne = 1.43 atm

Explanation:

Step 1: Data given

Volume = 3.0 L

Number of moles He = 4 moles

Number of moles Ne = 2 moles

Number of moles Ar = 1 mol

Total pressure = 5 atm

Step 2: Calculate total moles

Total moles = 4 moles + 2 moles + 1 mol

Total moles = 7 moles

Step 3: Calculate the mol ratio

Mol ratio = moles / total mol

Mol ratio He = 4 moles / 7 moles = 0.571

Mol ratio Ne = 2 moles / 7 moles = 0.286

Mol ratio Ar = 1 mol / 7 moles = 0.143 moles

Ste p4: Calculate partial pressure

PArtial pressure = mol ratio * total pressure

Partial pressure of Ne = mol ratio Ne * total pressure

Partial pressure of Ne = 0.286 * 5 atm

Partial pressure of Ne = 1.43 atm

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3 years ago

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