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Julli [10]
3 years ago
5

30g of naoh is dissolved in 1.5 liter solution the active mass of naoh is?

Chemistry
1 answer:
Pepsi [2]3 years ago
7 0

Answer:

0.5mol/L

Explanation:

First, let us calculate the number of mole NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH from the question = 30g

Number of mole = Mass /Molar Mass

Number of mole = 30/40 = 0.75mol

Volume = 1.5L

Active mass = mole/Volume

Active mass = 0.75mol/1.5L

Active mass = 0.5mol/L

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Solve first for the number of moles of sodium given that the mass is 2500 g by dividing the given mass by the molar mass of sodium. 
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Since in every mole of NaCl, there is only one mole of sodium then, we conclude that there are also 108.7 moles of NaCl. Multiplying the number of moles to the molar mass of sodium chloride (58.44), the answer would be 6,352.17 grams.
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