Answer:
the answer is A
Explanation:
since during a cold front the cold air replaces the warm air
Answer:Use the K L M N shell orbit
Explanation: Valence electrons are those electrons on the outermost shell of an atomic nucleus.
The K L M N electron shell is named by a spectroscopist called Charles G. Barkla, who discovered the A X-rays ( high energy rays) and the B X-rays ( low energy rays), he later renamed the A X-rays K X-rays which is the Energy level orbit, and the B X-rays was also renamed to be the L M N and so on.
PLEASE SEE PICTURE ATTACHED
THE PICTURE SHOWS HOW TO DETERMINE VALENCE ELECTRON USING THE As AND B's WHICH ARE THE K L M N SHELL ORBIT, USING SILICON AS AN EXAMPLE.
The maximum number of electron in the K orbit is 2
The maximum number of electron in the L M N shell is 8
Therefore the number of electron found in the outermost shell becomes the number of Valence electron in that element.
The higher the entropy the lower the reaction rate
M=pV p(density) v(volume)
V=nRT/P
Answer:
Ksp = 2.74 x 10⁻⁵
Explanation:
The solubility equilibrium for Ca(OH)₂ is the following:
Ca(OH)₂(s) ⇄ Ca²⁺(aq) + 2 OH⁻(aq)
I 0 0
C + s + 2s
E s 2s
According to the ICE table, the expression for the solubility product constant (Kps) is:
Ksp = [Ca²⁺] x ([OH⁻])² = s x (2s)² = 4s³
Then, we calculate Ksp from the solubility value (s):
s = 0.019 M
⇒ Ksp = 4s³ = 4 x (0.019)³ = 2.74 x 10⁻⁵