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3 years ago

All organic molecules have what element in common

Chemistry

2 answers:

joja [24]3 years ago

6 0

Every organic molecules/compound contains carbon (c).

Some other very abundant are hydrogen, nitrogen, oxygen, phosphorus, and sulfur.

I learned this with the acronym CHNOPS.

C - Carbon

H - Hydrogen

N - Nitrogen

O - Oxygen

P - Phosphorus

S - Sulfur

Hope this helps!

kari74 [83]3 years ago

6 0

<u>Answer:</u> The elements which are common for all organic molecules is hydrogen and carbon.

<u>Explanation:</u>

Another name for organic molecules are hydrocarbons. This means that the molecules which consist of hydrogen and carbon atoms is an organic compound.

For Example:

$H_2O\text{ and }CO_2$ are not organic compounds, because in water, carbon is not there and in carbon dioxide, hydrogen is not there. But, $CH_4$ is an organic compound because hydrogen and carbon both are present.

Hence, hydrogen and carbon elements are common to all organic molecules.

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3 years ago

Read 2 more answers

Who has the greater boiling point C2H6or C2H50H

hichkok12 [17]

Answer:

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Explanation:

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3 years ago

Calculate the molar solubility of PbBr2 (Ksp = 4.67x10-6) in 0.10M NaBr solution.

Softa [21]

Explanation:

$PbBr_{2}$ will dissociate into ions as follows.

$PbBr_{2}(s) \rightleftharpoons Pb^{2+}(aq) + 2Br^{-}(aq)$

Hence, $K_{sp}$ for this reaction will be as follows.

$K_{sp} = [Pb^{2+}][Br^{-}]^{2}$

We take x as the molar solubility of $PbBr_{2}$ when we dissolve x moles of solution per liter.

Hence, ionic molarities in the saturated solution will be as follows.

$[Pb^{2+}]$ = $[Pb^{2+}]_{o}$ + x

$[Br^{-}]^{2}$ = $[Br^{-}]_{o}$ + 2x

So, equilibrium solubility expression will be as follows.

$K_{sp}$ = $([Pb^{2+}]_{o} + x)([Br^{-}]_{o} + 2x)^{2}$

Each sodium bromide molecule is giving one bromide ion to the solution. Therefore, one solution contains $[Br^{-}]_{o}$ = 0.10 and there will be no lead ions. So, $[Pb^{2+}]_{o}$ = 0

So, $[Br^{-}]_{o} + 2x$ will approximately equals to $[Br^{-}]_{o}$ .