Answer: There are 1566 joules of heat needed to raise the temperature of 30.0 g of aluminum from 22°C to 80°C, if the specific heat of aluminum is 0.90 J/g°C.
Explanation:
Given: Mass = 30.0 g
Specific heat = 
Formula used to calculate the heat energy requires is as follows.
where,
q = heat energy
m = mass of substance
C = specific heat capacity of substance
= initial temperature
= final temperature
Substitute the values into above formula as follows.
Thus, we can conclude that there are 1566 joules of heat needed to raise the temperature of 30.0 g of aluminum from 22°C to 80°C, if the specific heat of aluminum is 0.90 J/g°C.
A valence electron structure would be like this 1s^2 2s^2 2p^6 etc
1s^2 would be 2, 2s^2 would be 4, 2p^6 would be 12 and so on and so forth.
Answer:
Sample response:
The costs of using both renewable and nonrenewable resources depend on the extent of the use. If renewable resources are managed wisely, the use of the resource will not exceed the rate at which it is replenished. In this instance the cost of using renewable resources can be minimized, if not entirely eliminated. The cost of using nonrenewable resources is harder to minimize because nonrenewable resources cannot be replenished at the rate at which they are used. The environmental impact of using nonrenewable resources such as fossil fuels is greater than just the loss of the resource itself. Other impacts such as acid rain, global warming, and atmospheric pollution can result from the use of nonrenewable resources.
Explanation:
2021 edge
have a nice day
No it can't. To be a molecular compound it should <span>contains at least two different elements. As it is made up of only gold (Au) atoms it violates the above requirement.</span>
Answer:
CaCO3(s) <==> Ca2+(aq) + CO3 2-(aq)
Let X = the amount of CaCO3 dissolved in Na2CO3 or the amount of each ions formed i.e. Ca2+ and CO3 2–. Then, put this into the formula :
Ksp = [Ca2+] [CO3 2-]
5 × 10^-9 = [X]*[X]
X^2 = 5 × 10^-9
X = √5 × 10^-9
X = 7.07 x 10^-5 mole/L
So, the amount of CaCO3 dissolved in 0.1M Na2CO3 or the amount of Ca2+ and CO3 2- ions produced is 7.07 x 10^-5 mole/L
