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weqwewe [10]
4 years ago
10

A teacher performing demonstration finds that a piece of cork displaces 23.5 ml of water. The piece of cork has a mass 5.7 g. Wh

at is the density of the cork ?
Physics
1 answer:
Sedbober [7]4 years ago
8 0

Answer: 0.24g/ml

Explanation:

Given that:

Volume of water displaced = 23.5 ml

Mass of cork = 5.7 g

Density of the cork = ?

Recall that density is obtained by dividing the mass of a substance by the volume of water displaced.

i.e Density = Mass/volume

Density = 5.7g /23.5ml

Density = 0.24g/ml

Thus, the density of the piece of cork is 0.24g/ml

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3 years ago
An unknown source plays a pitch of middle C (262 Hz). How fast would the sound wave from this source have to travel to raise
Viefleur [7K]

Answer:

The sound travels at v_{s}=11.4 \mathrm{m} / \mathrm{s}

Option: c

Explanation:

Unknown source plays of middle C (fs) = 262 Hz

The sound wave from this source have to travel to raise the pitch to C sharp is (fd) = 272 Hz

\begin{array}{l}{velocity of sound in air(v)=343 \mathrm{m} / \mathrm{s}, f_{\mathrm{s}}=262 \mathrm{Hz}, f_{\mathrm{d}}=271 \mathrm{Hz}} \\ {velocity of receiver(v_{\mathrm{d}})=0 \mathrm{m} / \mathrm{s},velocity of source( v_{\mathrm{s}}) \text { is unknown }}\end{array}

\text { Speed of sound } \mathrm{V}_{\mathrm{S}}=343 \mathrm{m} / \mathrm{s}

f_{\mathrm{d}}=f_{\mathrm{s}}\left(\frac{v-v_{\mathrm{d}}}{v-v_{\mathrm{s}}}\right)

\frac{f_{d}}{f_{s}}=\left(\frac{v-v_{d}}{v-v_{s}}\right)

\left(v-v_{s}\right)=\frac{f_{s}}{f_{d}}\left(v-v_{d}\right)

v_{s}=v-\frac{f_{s}}{f_{d}}\left(v-v_{d}\right)

Substitute the given values in the formula,

v_{s}=343+\frac{262}{271}(343-0)

v_{s}=343+0.966(343)

v_{s}=343-331.33

v_{s}=11.4 \mathrm{m} / \mathrm{s}

Therefore, The sound travels at v_{s}=11.4 \mathrm{m} / \mathrm{s}

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0.857 cm

Explanation:

We are given that:

The focal length for a convex lens to be (f) = 1.5cm

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By applying the lens formula:

\dfrac{1}{f} = \dfrac{1}{u}+\dfrac{1}{v}

By rearrangement and making (v) the subject of the above formula:

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