Answer:
Explanation:
PE = mgh where m is the mass in kg, g is the pull of gravity which is 9.8, and h is the height of the object above the point to which it could possibly fall, measured in meters. Plugging in:
PE = 10(9.8)(20) so
PE = 1960 J
This should be rounded to 1 sig fig according to the rules of sig fig and your numbers here, but I imagine you're not following them all that much. It should be 2000 J
Answer:
C. Replacing one gas by another under the same conditions, has no effect on pressure.
Explanation:
Ideal gas:
A gas is treated as an ideal gas if temperature is high and pressure is low.
Kinetic energy for ideal gas given as
So when temperature of gas is increases then Average molecular kinetic energy will also increases.
The size of molecule is negligible as compare to the dimension of container. It mean that volume occupied by molecule is less as compare to the volume of container.
The between molecules is perfectly elastic.
Ideal gas equation
P V = m R T
So the option C is not always true.
Answer:no it is staying the same speed
Explanation:
Energy and momentum are always conserved. Kinetic energy is not conserved in an inelastic collision though. And that is because it is converted to another form of energy
Answer:
ma+mgsinh0+f=F∴(25)(0.75)+(25)(10)sinh0+μkN=F∴18.75+(250)(0.6h)+μk(mgcosh0=F⟹18.75+150+μk((25)(10)(0.76))=500∴168.75+μk(190)=500⟹μk(190)=331.25⟹μk=1.74
Explanation:
