Nodes and antinodes.are part of an _____ wave A active B standing

Concept Simulation 2.3 provides some background for this problem. A ball is thrown vertically upward, which is the positive dire

KATRIN_1 [288]

Answer:

39 m/s

Explanation:

Hi!

The equation of motion of the ball is:

$y(t) = y_0 + v_{0y}t-(1/2)(9.8 m/s^2)t^2$

Where y_0 is the initial horizontal position, which we will take as zero.

v_0y is the initial velocity and t is the time

To find the initial velocity we will set y(7.96s) = 0

$0 = v_{0y} (7.96 s)-(4.9 m/s^2)(7.96 s)^2\\v_{0y} =(4.9 m/s^2) (7.96 s)\\v_{0y}=39.004 m/s$

8 0

3 years ago

A car accelerates uniformly in a straight line

julia-pushkina [17]

The car travels a distance d from rest with acceleration a after time t of

d = 1/2 a t²

It covers 69 m with 2.8 m/s² acceleration, so that

69 m = 1/2 (2.8 m/s²) t²

t² = 2 (69 m) / (2.8 m/s²)

t ≈ 7.02 s

where we take the positive square root because we're talking about time *after* the car begins accelerating.

8 0

3 years ago

a student uses a simple machine to help lift a load.when 40N of input force is applied to the machine it is able to lift 160N .w

Akimi4 [234]

4 to 1

Explanation If you look at it as a fraction 160/40 and you reduce it down as far as you can you get 4/1

3 0

3 years ago

A positively charged particle of mass 7.2 x 10-8 kg is traveling due east with a speed of 88 m/s and enters a 0.6-T uniform magn

Marianna [84]

Answer:

q = 8.57 10⁻⁵ mC

Explanation:

For this exercise let's use Newton's second law

F = ma

where force is magnetic force

F = q v x B

the bold are vectors, if we write the module of this expression we have

F = qv B sin θ

as the particle moves perpendicular to the field, the angle is θ= 90º

F = q vB

the acceleration of the particle is centripetal

a = v² / r

we substitute

qvB = m v² / r

qBr = m v

q = $\frac{m\ v}{B\ r}$

The exercise indicates the time it takes in the route that is carried out with constant speed, therefore we can use

v = d / t

the distance is ¼ of the circle,

d = $\frac{1}{4} \ 2\pi r$

d = $\frac{\pi }{2r}$

we substitute

v = $\frac{\pi r}{2t}$

r = $\frac{2 \ t \ v}{\pi }$

let's calculate

r = $\frac{2 \ 2.2 \ 10^{-3} \ 88}{\pi }$ 2 2.2 10-3 88 /πpi

r = 123.25 m

let's substitute the values

q = $\frac{ 7.2 \ 10^{-8} \ 88}{ 0.6 \ 123.25}$ 7.2 10-8 88 / 0.6 123.25

q = 8.57 10⁻⁸ C

Let's reduce to mC

q = 8.57 10⁻⁸ C (10³ mC / 1C)

q = 8.57 10⁻⁵ mC

4 0

2 years ago

nolan ryan has the record for having the speediest fastball in baseball. he could pitch one at 148 i/sec. what is that speed in

Klio2033 [76]

The speed of the ball is 101miles/hr.

A mile is a unit of length that is exactly 1,609.344 metres long. Similarly, 5,280 feet or 1,760 yards make up one mile. The mile is an imperial and common US measurement of distance.

We just have to deal with unit conversions.

One mile is 5280 feet, or 1 ft = 0.000189

The speed of the ball in miles per hour is

$\frac{148ft}{1sec} . \frac{1mile}{5280ft} .\frac{60s}{1min} .\frac{60min}{1hr}$

So, the speed of the ball in miles per hour is 101miles/hr.

Learn more about miles here;

brainly.com/question/23245414

#SPJ4

5 0

1 year ago