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2 years ago

To heat the water in the tank from 50°C to 58°C the immersion heater transfers

Physics

1 answer:

LenKa [72]2 years ago

4 0

Let's see

∆T=58-50=8°C

$\\ \rm\Rrightarrow Q=mc\Delta T$

$\\ \rm\Rrightarrow 4032=4200(8)m$

$\\ \rm\Rrightarrow 4032/8=4200m$

$\\ \rm\Rrightarrow 504=4200m$

$\\ \rm\Rrightarrow m=0.12kg$

$\\ \rm\Rrightarrow m=120g$

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ASE (National Institute for Automotive Service Excellence) certified professionals must be retested every _______ years to keep

Bess [88]

Hi,

The correct answer is C. five

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3 years ago

which of this is not example of simple machine? A) a crowbar,B)a knife,C)a bicycle,D)a wheelchair ramp

DaniilM [7]

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3 years ago

A rifle bullet with mass 8.00g strikes and embeds itself in a block with mass 0.992kg that rests on a frictionless, horizontal s

mafiozo [28]

Answer:

block velocity v = 0.09186 = 9.18 10⁻² m/s and speed bollet v₀ = 11.5 m / s

Explanation:

We will solve this problem using the concepts of the moment, let's try a system formed by the two bodies, the bullet and the block; In this system all scaffolds during the crash are internal, consequently, the moment is preserved.

Let's write the moment in two moments before the crash and after the crash, let's call the mass of the bullet (m) and the mass of the Block (M)

Before the crash

p₀ = m v₀ + 0

After the crash

$p_{f}$ = (m + M) v

p₀ = $p_{f}$

m v₀ = (m + M) v (1)

Now let's lock after the two bodies are joined, in this case the mechanical energy is conserved, write it in two moments after the crash and when you have the maximum compression of the spring

Initial

Em₀ = K = ½ m v2

Final

E $m_{f}$ = Ke = ½ k x2

Emo = E $m_{f}$

½ m v² = ½ k x²

v² = k/m x²

Let's look for the spring constant (k), with Hook's law

F = -k x

k = -F / x

k = - 0.75 / -0.25

k = 3 N / m

Let's calculate the speed

v = √(k/m) x

v = √ (3/8.00) 0.15

v = 0.09186 = 9.18 10⁻² m/s

This is the spped of the block plus bullet rsystem right after the crash

We substitute calculate in equation (1)

m v₀ = (m + M) v

v₀ = v (m + M) / m

v₀ = 0.09186 (0.008 + 0.992) /0.008

v₀ = 11.5 m / s

6 0

3 years ago

Dinah is playing cards with her friends, and it is her turn to deal. A card with a mass of 2.3 g slides 0.35 m along the table b

Inga [223]

Answer:

soln,

=2.3+0.35-0.24

=2.41 answer

4 0

2 years ago

When exposed to a radioactive source which emits 1.2-MeV gamma-rays, a particular material is found to have a half-value thickne

iren2701 [21]

Answer:E

Explanation:

It is given that Energy of gamma ray is E=1.2 Mev

Shielding effect can be measured by measuring the fraction of gamma rays blocked by shield. If certain thickness will able to block half the radiation then to block 75% radiation we need to add same amount of thickness in order to block the remaining radiation.

i.e. $\frac{E}{2}$ fraction is blocked by 10 cm thickness

then remaining radiation is $\frac{E}{2}$

another 10 cm thickness will block the remaining half radiation i.e. $\frac{1}{2}\times \frac{E}{2}=\frac{E}{4}$

so total 75 % radiation will be blocked

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3 years ago