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Alekssandra [29.7K]
3 years ago
11

Which is the most likely location in the home for mold growth? A) bathroom windows B) living room furniture C) computer keyboard

D) bedroom carpet E) wooden floor
Physics
2 answers:
TiliK225 [7]3 years ago
5 0

Answer:

A) bathroom windows

Explanation:

Mold will grow in places with a lot of moisture, such as around leaks in roofs, windows, or pipes, or where there has been flooding. The warm, indoor air can condense around cold, often drafty windows which creates moisture. If the moisture is not dried on the window sills and window casings/trim they become damp and allow for mold to grow. Windows that are not sealed well or have cracked or missing caulking are also prone to mold growth.

FinnZ [79.3K]3 years ago
3 0

Answer:

A

Explanation:

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The y-axis on a distance-time graph would be ____________. time distance speed
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Answer:

Distance

Explanation:

distance is in vertical axis,or y-axis and time is on the horizontal axis,or x-axis.

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3 years ago
A player kick the soccer ball from ground level and send it flying at an angle of 30° at a speed of 26M/S. What is the maximum h
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melisa1 [442]

Answer:

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4 0
3 years ago
During a race, a runner runs at a speed of 6 m/s. 2 seconds later, she is running at a speed of 10 m/s. What is the runner’s acc
Lapatulllka [165]
Let's calculate the average acceleration. It is the rate of changing speeds. Hence, we need to calculate the difference of speeds. 10-6=4 m/s. The rate is now \frac{4m/s}{2s} =2m/s^2.
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5 0
3 years ago
A woman is running around a playground while keeping an eye on her child who is on a swing set. The child is going back and fort
Nutka1998 [239]

Answer:

(a) 1500 m

(b) 2827.43m

Explanation:

Given that the time for one cycle of the swing is 1 s

The radius of the swing, R= 3.0m

The angle covered, \theta, by each swing is a quarter of the circle. i.e.

\Theta=\frac {\pi}{2}

Speed of running of women =5 m/s.

Time of running = 5 minutes= 5 x 60 secondes= 300 s.

(a) As distance= (speed) x (time)

So, the required distance= 5 x 300 m= 1500 m.

(b) As there are two swings in one cycle, so, the distance covered in one swing is the length of the circular shown in the figure.

As arc length, l= \theta R, where \theta is the angle, in radian, subtended by the arc at the center, and R is the radius of curvature of the arc.

So, the distance covered by the child in 1 swing = \frac {\pi}{2}\times 3 m=\frac{3\pi}{2}m.

In 1 cycle, there are 2 swings, so distance covered in 1 cycle = 3 \pi m.

Now, in 1 second there is 1 cycle, so in 5 minutes there will be 300 cycles.

So, the total distance covered by the child

= 3\pi\times 300 m= 2827.43 m.

3 0
3 years ago
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