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2 years ago

It takes 500W of power to move an object 96 m in 12 s. What force is being applied to the object?

Physics

1 answer:

Marianna [84]2 years ago

5 0

The force being applied to the object is calculated to be 62.5N.

<h3>POWER:</h3>

Power is the rate at which work is done. It is measured in watts (W). Power can be calculated by multiplying the force applied on a given object by its speed.

Power (P) = Force (F) × speed (V)

According to this question, it takes 500W of power to move an object 96 m in 12 s. The speed of the object in m/s is calculated as: 96m/12s = 8m/s.

The force applied on the object = 500/8

Force = 62.5N

Therefore, the force being applied to the object is calculated to be 62.5N.

Learn more about force at: brainly.com/question/1436187

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The following table lists the work functions of a few commonmetals, measured in electron volts.

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Answer:

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Explanation:

The equation for the photoelectric effect is

$\frac{hc}{\lambda}= \phi + K_{max}$

where

$\frac{hc}{\lambda}$ is the energy of the incident photon, with

h being the Planck constant

c is the speed of light

$\lambda$ is the wavelength of the photon

$\phi$ is the work function of the metal (the minimum energy needed to extract the photoelectron from the metal)

$K_{max}$ is the maximum kinetic energy of the emitted photoelectrons

In this problem, we have

$\lambda= 190 nm = 1.9\cdot 10^{-7}m$ is the wavelength of the incident photon

$K_{max}=4.0 eV$ is the maximum kinetic energy of the electrons

First of all we can find the energy of the incident photon

$E=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{1.90\cdot 10^{-7} m}=1.05\cdot 10^{-18} J$

Converting into electronvolts,

$E=\frac{1.05\cdot 10^{-18} J}{1.6\cdot 10^{-19} J/eV}=6.6 eV$

So now we can re-arrange the equation of the photoelectric effect to find the work function of the metal

$\phi = E-K_{max}=6.6 eV - 4.0 eV=2.6 eV$

So the metal is most likely Lithium, which has a work function of 2.5 eV.

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