Ask question

Ask question

All categories

3 years ago

8

If you were an Astronaut in the middle of the near side of the moon during a full moon, how would the ground around you look? Ho

w would the earth high in the sky look? Describe what is in sunlight and what is in darkness

1 answer:

Alenkasestr [34]3 years ago

6 0

Dark light a round ball and stuff

You might be interested in

I have a special thermos that has a vacuum chamber between my hot soup and its outside wall. Because my soup is isolated from it

bagirrra123 [75]

Answer:

C. My soup will cool down because of radiation.

Explanation:

Since, there is vacuum between hot soup and its outside wall, then heat can not flow through conduction and convection.

The heat then only flows through radiation.

Therefore, the soup will not cool down because of convection or conduction by because of radiation.

7 0

3 years ago

Elsie is finishing second grade. If she goes to school 147 day per year and she have 10 years of school left, how many days of s

ICE Princess25 [194]

Answer:

1,323 days left

Explanation:

147 x 10 = 1,470

1470 - 147 = 1,323

Hopefully this helps you :)

pls mark brainlest ;)

6 0

3 years ago

A sailor pulls a crate across the deck of a ship with a rope, exerting a horizontal force of 150. N. The crate, which has a mass

nata0808 [166]

Answer:

B

Explanation:

7 0

3 years ago

An amusement park ride consists of a rotating circular platform 8.26 m in diameter from which 10 kg seats are suspended at the e

VashaNatasha [74]

To solve this problem we will begin by finding the necessary and effective distances that act as components of the centripetal and gravity Forces. Later using the same relationships we will find the speed of the body. The second part of the problem will use the equations previously found to find the tension.

PART A) We will begin by finding the two net distances.

$r = \frac{8.26}{2} = 4.13m$

And the distance 'd' is

$d = lsin\theta$

$d = 1.14 sin 16.2\°$

$d = 0.318m$

Through the free-body diagram the tension components are given by

$Tcos\theta = mg$

$Tsin\theta = \frac{mv^2}{R}$

Here we can watch that,

$R = r+d$

Dividing both expression we have that,

$tan\theta = \frac{v^2}{Rg}$

Replacing the values,

$tan(16.2) = \frac{v^2}{(4.13+0.318)(9.8)}$

$v = 4.83371m/s$

PART B) Using the vertical component we can find the tension,

$Tcos\theta = mg$

$T = \frac{mg}{cos\theta}$

$T = \frac{(10+26.2)(9.8)}{cos(16.2)}$

$T = 369.42N$

6 0

3 years ago

Which is most important in the use of a camera photofl ash unit, the intensity of the light (the energy per unit area per unit t

maria [59]

Answer:

intensity of the light (the energy per unit area per unit time)

Explanation:

The photoflash capacitor is an electrolytic capacitor that is also used in flash cameras, professional illumination and solid-state laser supply. Their general purpose is to briefly power a high-voltage flash tube, which can be used to illuminate photographic material or to alternately pump a laser rod.
Since the flash tube requires very little time to operate, photoflash capacitors are designed to supply high discharge current pulses without excessive internal heating.

5 0

3 years ago